(a) We must first look at the formulas of the velocities of each toy car. v1 =
-4.2 + 2.60t. v2 = 5.20. When the two cars have equal speed, then
v1 = v2
-4.2 + 2.60t = 5.20
2.60t = 9.40
t = 3.62 s
(b) Their speed would then be 5.20 m/s. The toy car does not change speed since it doest not have any acceleration.
(c) The two cars will pass each other when their positions are equal.
x1 = 13.5 - 4.2t + 0.5*2.60t^2
x2 = 8.5 + 5.20t
x1 = x2
13.5 - 4.2t + 1.30t^2 = 8.5 + 5.20t
1.30t^2 - 9.40t + 5.0 = 0
t = 6.65s or t = 0.58 s
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Answer:
i think it is f i could be wrong-
First of all you need to have in mind the following data:
<span>Mass of Mars: 6.43 x 10^23 kg
Radius of Mars: 3.40 x 10^6 m
Formulas: F = G(m1)(m2)/(r^2), m1 = F(r^2)/G(m2), m2 = F(r^2)/G(m1), F = ma
G = 6.67 x 10^-11
</span><span> We can say that the first and second objects with mass can be called as following:
m1= centre of Mars
m2 = will be the ball.
</span>The distance between them = the radious of mars.
I believe the answer is C. It will maintain its state of motion
Answer:
13.8 N
Explanation:
Pressure on the one end of the hydraulic system = Pressure on the other end
Pressure = Force / Area where Force is in Newton, area is in m²
so Force of one end (F1) / area of that end = force of the other end (F2) / area of that end
3112 / ( 707 /10000) in m² = F2 / ( 3.14 / 10000) in m²
cross multiply
44016.97 × 0.000314 = 13.82 N
