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bogdanovich [222]
4 years ago
6

Imagine that a hypothetical life form is discovered on our moon and transported to Earth. On a hot day, this life form begins to

sweat, and it is determined that the heat of vaporization of its sweat is 107 cal/g. The scientist observing the extraterrestrial life form also begins to sweat. The heat of vaporization of the scientist's sweat is 580 cal/g at the skin's surface. If both the extraterrestrial life form and the scientist lose 735 g of sweat over the course of one hour, calculate the heat lost by each body from the vaporization of sweat.
Physics
1 answer:
almond37 [142]4 years ago
4 0

Answer:

The heat of vaporization 580 cal/g times 602g = cal in human  and do the same for life form.

Explanation:

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Explanation:

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3 years ago
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gladu [14]

Answer:

50.4 N

Explanation:

Q1 = Q

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The force is given by

F = \frac{KQ_{1}Q_{2}}{d^{2}}

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Now,

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Q4 = 7 Q

distance = d/3

F' = \frac{9KQ_{3}Q_{4}}{d^{2}}

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Divide equation (2) by equation (1), we get

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3 years ago
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klemol [59]

Answer:

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6 0
3 years ago
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mixer [17]

Answer:

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Explanation:

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