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Mnenie [13.5K]
4 years ago
3

You are given a liquid mixture to identify as a colloid, suspension or solution. When you shine light from a laser pointer the b

eam passes through without scattering any light.
The mixture is most likely a)suspension
B) not enough info
C) colloid)
D) solution
Chemistry
2 answers:
gogolik [260]4 years ago
8 0

<u>Answer:</u> The correct answer is Option D.

<u>Explanation:</u>

Mixtures are defined as the combination of two or more pure substances in which every pure substance retains its individual chemical properties. They are classified into three types:

  1. <u>Solution:</u> The mixtures are defined as solutions when the particle size is between 0.1 nm to 1 nm. In solutions, there is no physical boundary between dispersed phase and dispersed medium. When light is passed through these mixtures, they pass through.
  2. <u>Colloid:</u> The mixtures are defined as colloids when the particle size is between 2 to 1000 nm.  In colloids, physical boundary between dispersed phase and dispersed medium is seen. When light is passed through these mixtures, they scatter the light.
  3. <u>Suspension:</u> The mixtures are defined as suspension when the particle size is greater than 1000 nm. In suspension, physical boundary is seen between the dispersed phase and dispersed medium. When light is passed through these mixtures, the particles scatter the light.

From the above information, the correct answer is Option D.

rosijanka [135]4 years ago
6 0
It is most likely a solution. 

Solutions are always clear and transparent, suspensions are cloudy and at least two substances are visible, and colloids are cloudy but homogeneous. 
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you have a lead ball with a mass of 420 g. the density of lead is 10.5 g/cm³. what is the volume of the ball
IrinaK [193]

Answer:

The answer is

<h2>40.0 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}

From the question

mass = 420 g

density = 10.5 g/cm³

The volume is

volume =  \frac{420}{10.5}  \\

We have the final answer as

<h3>40.0 mL</h3>

Hope this helps you

7 0
3 years ago
A 100g of sample of a compound is combusted in excess oxygen and the products are 2.492g of CO2 and 0.6495 of H2O. Determine the
ruslelena [56]

The empirical formula : C₁₁O₁₄O₃

<h3>Further explanation</h3>

The assumption of the compound consists of C, H, and O

mass of C in CO₂ =

\tt \dfrac{12}{44}\times 2.492=0.680~g

mass of H in H₂O =

\tt \dfrac{2.1}{18}\times 0.6495=0.072~g

mass of O :

mass sample-(mass C + mass H)

\tt 1-(0.68+0.072)=0.248`g

mol of  C :

\tt \dfrac{0.68}{12}=0.056

mol of H :

\tt \dfrac{0.072}{1}=0.072

mol of O :

\tt \dfrac{0.248}{16}=0.0155

divide by 0.0155(the lowest ratio)

C : H : O ⇒

\tt \dfrac{0.056}{0.0155}\div \dfrac{0.072}{0.0155}\div \dfrac{0.0155}{0.0155}=3.6\div 4.6\div  1\\\\\dfrac{11}{3}\div \dfrac{14}{3}\div \dfrac{3}{3}=11:14:3

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3 years ago
In a chemical reaction*
Bess [88]

Answer:

1st one is correct

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3 years ago
11. As early as 1938. the use of NaOH was suggested as a means of removing CO2 from the cabin of a spacecraft according to the f
vagabundo [1.1K]

For a (unbalanced) reaction: NaOH +CO2-Na2CO3 + H2O, the moles of NaOH and moles of each product are formed are mathematically given as

a) Moles of NaOH =44.05

b)   Moles of Na2CO3=21.0

  • Moles of H2O= 21.0

<h3>What is the moles of NaOH and what moles of each product are formed?</h3>

Generally, the equation for the Chemical reaction  is mathematically given as

2 NaOH(aq)+ CO2(g)------> Na2CO3(aq)+ H2O(l)

Therefore

Moles of CO2= 925/44

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Hence

Moles of NaOH = 2 x Moles of CO2

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Moles of NaOH =44.05

In conclusion

Moles of Na2CO3 925/44

Moles of Na2CO3=21.0

And

Moles of H2O= 925/44

Moles of H2O= 21.0

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kolbaska11 [484]

Answer:

The FALSE statement is: It requires CO2.

Explanation:

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