Question

Can someone help me asap please?!?!?!?

Answer 1

Assuming you mean something like
$(\frac{3}{4})(\frac{8}{9})(\frac{15}{16})(\frac{24}{25})(\frac{35}{36})(\frac{48}{49})(\frac{63}{64})(\frac{80}{81})(\frac{99}{100})$

so

remember $(\frac{a}{b})(\frac{c}{d})=\frac{ac}{bd}$
so
$(\frac{3}{4})(\frac{8}{9})(\frac{15}{16})(\frac{24}{25})(\frac{35}{36})(\frac{48}{49})(\frac{63}{64})(\frac{80}{81})(\frac{99}{100})=$
$\frac{(3)(8)(15)(24)(35)(48)(63)(80)(99)}{(4)(9)(16)(25)(36)(49)(64)(81)(100)}$
factor out some things
$\frac{(3)(2^3)(3)(5)(2^3)(3)(5)(7)(2^4)(3)(3^2)(7)(2^4)(5)(3^2)(11)}{(2^2)(3^2)(2^4)(5^2)(2^2)(3^2)(7^2)(2^6)(3^4)(2^2)(5^2)}=$
$\frac{(2^{14})(3^8)(5^3)(7^2)(11)}{(2^{16})(3^8)(5^4)(7^2)}=$
$\frac{11}{(2^2)(5^1)}=\frac{11}{20}$