Answer:

Explanation:
From work energy theorem
Work done by all forces = Change in kinetic energy
Lets take
m= mass of object
h=height from the ground surface
initial velocity of object = 0 m/s
The final velocity of object is v
Work done by gravitational force = m g . h
The final kinetic energy = 1/2 m v²
So
Work done by all forces = Change in kinetic energy
m g h = 1/2 m v² - 0
v² = 2 g h

Answer:
elastic partial width is 2.49 eV
Explanation:
given data
ER E = 250 eV
spin J = 0
cross-section magnitude σ = 1300 barns
peak P = 20ev
to find out
elastic partial width W
solution
we know here that
σ = λ²× W / ( E × π × P ) ...................1
put here all value
σ = (0.286)² × W ×
/ ( 250 × π × 20 )
1300 ×
= (0.286)² × W ×
/ ( 250 × π × 20 )
solve it and we get W
W = 249.56 ×
so elastic partial width is 2.49 eV
Answer:
a). P=11.04kW
b). Pmax=11.38 kW
c). Wt=6423.166kJ
Explanation:
The power of the motor when the speed is constant is the work in a determinate time.

The work is the force the is applicated in a distance so
W=F*d
replacing:
and
determinate distance in time is velocity so
a).


b).
The maximum power must the motor provide, is the maximum force with the maximum speed of the motor in this case
The first step is find the acceleration so

The maximum force is when the car is accelerating so

so the maximum force is the maximum force by the maximum speed

c).
The total energy transfer without any friction is the weight move in the high axis y in this case, so is easy to know that distance
W=m*g*h
h=Length*sin(33.5)
W=m*g*Length*sin(33.5)
W=950 kg*9.8* 1250m*sin(33.5)
W=6423166.667 kJ
W=6423.166 kJ
She does 200J .
We know she uses 20N of force and 10m is the distance. We multiply both numbers and we are given our answer of 200J. Hope this was helpful. :)