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ICE Princess25 [194]
3 years ago
5

Iron + Hydrochloric acid --> ?

Physics
2 answers:
marusya05 [52]3 years ago
8 0
<h3>Iron - Fe</h3>

<h3>Hydrochloric Acid- HCl</h3>

<h2><u>Solution</u></h2>

\bold{Fe  +2HCl \rightarrow FeCl _{}{ \tiny2}  + H{ \tiny{2}}}

\therefore \bold{\fbox{{Balanced}}}

Iron + Hydrochloric Acid \rightarrow Ferrous Chloride + Hydrogen

<h2>Hope This Helps You ❤️</h2>
Paladinen [302]3 years ago
6 0

Ferrous Chloride + Hydrogen

Chemical equation: Fe + 2HCl ->FeCl2 + H2

<em>Feel free to mark as brainliest :D</em>

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In the oscillating spring ball system, where is the velocity of the ball the greatest?
nlexa [21]

The speed of an object in a mass-spring system is given under the function

v = \pm \sqrt{\frac{k}{m}(A^2-x^2)}

Here,

m = mass

k = Spring constant

A = Amplitude

x = Position

When the position is at the equilibrium point (x = 0), the speed will be maximum, and could even be expressed as

v_{max}= A\sqrt{\frac{x}{m}}

So the correct answer is B.

6 0
3 years ago
A ball has a diameter of 3.77 cm and average density of 0.0839 g/cm3. What force is required to hold it completely submerged und
mestny [16]

Answer:

0.25 N

Explanation:

The density of the ball (\rho_b) = 0.0839 g/cm³ = 83.9 kg/m³

The density of water (\rho_w) = 1000 kg/m³

diameter = 3.77 cm = 0.0377 m

radius of ball = 0.0377/2 = 0.01885 m

The volume (V) = \frac{4}{3} \pi r^3=\frac{4}{3}*\pi*0.01885^3=2.8*10^{-5}\ m^3

Let us assume the acceleration due to gravity (g) = 9.8 m/s²

Hence:

The force is required to hold it completely submerged under water (F) is:

F=\rho_w Vg-\rho_b Vg=1000*(2.8*10^{-5})*9.81-83.9*(2.8*10^{-5})*9.81\\\\

F = 0.25 N

7 0
3 years ago
Ice wedging is brought about by ____.
grigory [225]
<span>Ice wedging is caused by water freezing and thawing. During this process of conversion of the water into ice the water is expanded and crack in the ground is formed. These cracks are formed duing the winter, when the water freezes, expands and the enlarges the cracks. In summer, when the ice melts more water is accumulated in the cracks and the process repeats.</span>
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3 years ago
What properties does a gas have in terms of shape and volume
insens350 [35]
Gases, liquids and solids are all made up of atoms, molecules, and/or ions, but the behaviors of these particles differ in the three phases. The following figure illustrates the microscopic differences.

Microscopic view of a gas Microscopic view of a liquid. Microscopic view of a solid.
Microscopic view of a gas. Microscopic view of a liquid. Microscopic view of a solid.
Note that:

Particles in a:
gas are well separated with no regular arrangement.
liquid are close together with no regular arrangement.
solid are tightly packed, usually in a regular pattern.
Particles in a:
gas vibrate and move freely at high speeds.
liquid vibrate, move about, and slide past each other.
solid vibrate (jiggle) but generally do not move from place to place.
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7 0
3 years ago
Two loudspeakers (A and B) are 3.20m apart and emitting a sound with a frequency of 400Hz. An observer is 2.10m directly in fron
TiliK225 [7]

Answer:

The observer hears a loud sound

Explanation:

In order to know if the observer hears a loud or a quiet sound, you need to know if there is a constructive or destructive interference between the sound waves of the loudspeakers.

You first calculate the distance between the observer and the loudspeakers.

The distances are given by:

d1: distance to loudspeaker A = 2.10m

d2: distance to loudspeaker B

d_2=\sqrt{(3.20m)^2+(2.10m)^2}=3.827m

Next, you calculate the wavelength of the sound waves by using the following formula:

\lambda=\frac{v_s}{f}

vs: speed of sound =  343 m/s

f: frequency of the waves = 400Hz

λ: wavelength

\lambda=\frac{343m/s}{400Hz}=0.8575m

Next, you calculate the path difference between the distance from the observer to the loudspeakers:

\Delta d=3.827m-2.10m=1.727m

You obtain a constructive interference (loud sound) if the quotient between the wavelength of the sound and the difference path is an integer:

\frac{\Delta d}{\lambda}=\frac{1.727m}{0.857}\approx2

Then, there will be a constructive interference, and the sound who the observer hears is loud.

5 0
3 years ago
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