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Ray Of Light [21]
4 years ago
15

Which of the following terms refers to any push or pull on an object

Physics
1 answer:
Murljashka [212]4 years ago
3 0
Its either B. force or A. net force but I will go with force because forces can either push or pull I hope it help you.
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2. Who bombarded molybdenum with atomic number (Z=42) with fast moving<br>neutrons?<br>​
Dominik [7]

Answer:

This question appears incomplete

Explanation:

This question appears incomplete, however Molybdenum-99 (⁹⁹Mo) is produced by bombarding Molybdenum-98 (⁹⁸Mo) with fast moving neutrons (¹₀n) as shown below

⁹⁸₄₂Mo + ¹₀n ⇒  ⁹⁹₄₂Mo + ⁰₀γ

This reaction is a nuclear caption reaction (which occurs in a nuclear reactor) for the production of Molybdenum-99 (⁹⁹Mo) which serves as a "precursor" for the production of medically viable/ Clinical Grade Technutium-99m (⁹⁹Tc) through Ion-exchange technique.

3 0
4 years ago
The force that attracts earth to an object is equal to and opposite the force that earth exerts on the object. Explain why earth
alexandr402 [8]

Answer:

Because of heavy mass

Explanation:

When force acts on a body it tends to accelerate the body. The acceleration produced in the body depends on two things:

1). Magnitude of force

2). Mass of the body

F= ma

⇒ a = F/m  

As the force exerted on earth and another object are the equal in magnitude but opposite in direction. This forces will accelerate the object toward the earth but can't accelerate the earth as earth has very high mass.

a = F/m

This force tends to accelerate the earth but but due to earth's inertia the earth does not accelerate.

7 0
3 years ago
A block is projected up a frictionless inclined plane with initial speed v0 = 1.72 m/s. The angle of incline is θ = 44.8°. (a) H
Snowcat [4.5K]

Explanation:

Given

initial velocity(v_0)=1.72 m/s

\theta =44.8{\circ}

using v^2-u^2=2as

Where v=final velocity (Here v=0)

u=initial velocity(1.72 m/s)

a=acceleration   (gsin\theta )

s=distance traveled

0-(1.72)^2=2(-9.81\times sin(44.8))s

s=0.214 m

(b)time taken to travel 0.214 m

v=u+at

0=1.72-gsin(44.8)\times t

t=\frac{1.72}{9.8\times sin(44.8)}

t=0.249 s

(c)Speed of the block at bottom

v^2-u^2=2as

Here u=0 as it started coming downward

v^2=2\times gsin(44.8)\times 0.214

v=\sqrt{2.985}

v=1.72 m/s

3 0
4 years ago
a boy looks at the reflection of his digital watch in a plane mirror and thinks the time is 10:11. what is the correct time?
Gekata [30.6K]

Answer:

11:10 will be the time. reflection causes the object to be flipped when you see its image at the mirror

6 0
3 years ago
A man works on a striaght road from his home to market 2.5km away dwith a speed of 5km/h.Finding the market closed, he instantly
umka21 [38]

Answer:

5.625km/h

Explanation:

We are given that

Distance between home and market, d=2.5 km

Speed, v1=5km/h

Speed, v2=7.5 km/h

We have to find the average speed of the man over the interval of time 0 to 40min.

Time,t=\frac{distance}{speed}

Using the formula

t_1=\frac{2.5}{5}=0.5 h=0.5\times 60=30 min

1 hour =60 min

t_2=\frac{2.5}{7.5}=\frac{1}{3}hour=\frac{60}{3}=20min

Distance traveled by man in 10 min with speed 7.5 km/h=\frac{2.5}{20}\times 10=2.5/2km

Therefore,

Total distance covered=2.5+2.5/2=3.75 km

Time=40 min=40/60=2/3 hour

Average speed=\frac{total\;distance}{total\;time}

Average speed=\frac{3.75}{2/3}=5.625km/h

7 0
3 years ago
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