<h3>
Answer: Approximately 4.67 m/s^2</h3>
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Explanation:
Let's say you want to push the brick to the right. The free body diagram will have an arrow pointing right on the rectangle (the brick) and the arrow is labeled with 35 N.
Friction always counteracts whatever force you apply. The friction force arrow will point left and be labeled with 7 N.
The net horizontal force is therefore 35-7 = 28 N and the direction is to the right. The positive net force means you've overcome the force of friction and the brick is moving.
F = 28 is the net force
m = 6 is the mass
a = unknown acceleration
F = m*a .... newton's second law
28 = 6a
6a = 28
a = 28/6
a = 4.67
The acceleration of the brick is approximately 4.67 m/s^2
This means that for every second, the brick's velocity is increasing by about 4.67 m/s.
Answer:
The answer would be the last option (the one with the arrow pointing sideways)
Explanation:
The arrow lost it's acceleration and is starting to go downwards but it isn't a straight slope down
#1 is sand dune , #2 glaciers , #3 sand sediments hence small mass and #4 is <span> moraine .</span>
Answer:
Pentane reacts with oxygen in a combustion reaction to produce carbon dioxide and water. C5H12 + O2 -> CO2 + H2O If you have 5.00 moles of pentane, how many moles of water will be produced? Hexane combusts in the presence of oxygen to produce carbon dioxide and water.
Explanation:
Answer:
<em>The velocity of the truck is 3.33 m/s</em>
Explanation:
<u>Law Of Conservation Of Linear Momentum
</u>
The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and velocity v is
P=mv.
If we have a system of bodies, then the total momentum is the sum of the individual momentums:
If some collision occurs, the velocities change to v' and the final momentum is:
In a system of two masses:
There are two objects: The m1=4000 Kg car and the m2=6000 Kg truck. The car was moving initially at v1=4 m/s and the truck was at rest v2=0. After the collision, the car moves at v1'=-1 m/s. We need to find the velocity of the truck v2'. Solving for v2':
Substituting:
The velocity of the truck is 3.33 m/s
