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aliina [53]
3 years ago
15

Using the formula, find the coefficient of skewness for each distribution, and describe the shape of the distribution.

Mathematics
1 answer:
inessss [21]3 years ago
5 0

Answer:

a) As =  0.67  right skewness

b) As =  -0.75  left skewness

c) As =  0   ( Symmetric )

d) As = 0.1 ( slightly unsimmetric ) right skewness

Step-by-step explanation:

We will use the formula

As = skewness coefficient

μ  = mean of distribution

Μ = median of distribution

And Pearson formula :     As = ( μ - Μ) / σ

a)  As = ( 10- 8 ) /3      =2/3  = 0.67

The distribution is right-skewness  (positive skewness)

b) As = ( 42 - 45 ) / 4  = -3/4 = -0.75

The distribution is left skewness  (negative skewness)

c) As = ( 18.6 - 18.6 )/ 1.5      = 0

The curve of the distribution is is symmetric

d) As = ( 98 - 97.6 ) / 4    = 0.4/4  = 0.1

The distribution is right skewness (slightly unsimmetric)

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Please i need help with the answers this is due later on today
Nutka1998 [239]

Answer:

384, 216, 290, 192, 384

1446, 1 roll

Step-by-step explanation:

For rectangular boxes, calculate the sum of each side, then multiply it by two.

Box 1: 2(18 x 5) + 2(18 x 4) + 2(5 x 4) = 364

Box 3: 2(11 x 8) + 2(8 x 3) + 2(3 x 11) = 290

Box 5 is a cube (all sides equal), so you can find 1 side's area and multiply it by 6.

Box 5: 6(8 x 8) = 384

For triangular boxes, calculate the edges, then find the triangular area using area = 0.5(base x height).

Box 2: (15 x 3) + (9 x 3) + (12 x 3) + 2(0.5)(9 x 12) = 216

Box 4: 2(13 x 2) + (10 x 2) + 2(0.5)(10 x 12) = 192

Total: 364 + 290 + 384 + 216 + 192 = 1446

Rolls of wrapping paper:

Area of 1 roll = 30 x 60 = 1800

Since 1446 is less than 1800, you only need 1 roll of wrapping paper.

8 0
3 years ago
Read 2 more answers
Ben's living room is a rectangular measuring 12 yards x 204" by how many feet does the length of the room exceed the with the le
Firlakuza [10]

Answer:

The length of the room exceeds the width by 19 feet

Step-by-step explanation:

From the question, the room measures 12 yards x 204", that 12 yards x 204 inches. To determine by how many feet the length of the room exceeds the width, we will first convert both units of measurement ( yards and inches) to feet.

To convert 12 yards to feet,

1 yard = 3 feet

∴ 12 yards will be 3 × 12 feet = 36 feet

To convert 204" to feet

12" = 1 foot

∴ 204" will be 204/12 feet = 17 feet

Hence, the room measures 36 feet × 17 feet

That is, Length of the room = 36 feet

and width of the room = 17 feet

Now, to determine by how many feet the length of the room exceeds the width, we will deduct the width of the room from the length of the room, that is,

36 feet - 17 feet = 19 feet

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3 years ago
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no

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3 years ago
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n200080 [17]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
Felicia places a rectangular rug that measures 10 feet by 11 feet in a triangular room with a base of 30 feet and height of 22 f
arsen [322]

Answer:

1. Area of rectangular rug is 110 ft^{2}

2. Area of triangular room is 330ft^{2}

Step-by-step explanation:

This problem bothers on the mensuration of flat shapes, rectangle and triangle.

step one

let us start by solving for the area of the rectangular rug

given data

Area A =  ?

Length l =  11 ft

Width w=  10 ft

we know that the area of a rectangle is expressed as

Area=Length * Width

substituting our given data we have

Area= 11*10\\Area= 110 ft^{2}

step two

let us  solve for the area of the triangular room

given data

Area A =  ?

base b =  30 ft

height  h=  22 ft

we know that the area of a triangle is expressed as

Area= \frac{1}{2} *base* height\\

substituting our given data we have

Area= \frac{1}{2} * 30* 22\\Area=\frac{660}{2} \\Area= 330 ft^{2}

8 0
3 years ago
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