Decrease the temperature and increase the presure
Answer:(a) 6CO2 (g) + 6H2O (l) → C6H12O6 (s) + 6O2 (g)
(b) 5.55*10^37photons
Explanation:
(a) Here we have to write a balanced thermochemical equation for formation of 1.00 mol of glucose.
In this question it has been given that Chlorophyll absorbs light in the 600 to 700 nm region,
1st we will write a chemical equation for biochemical process of photosynthesis is that CO2 and H2O form glucose (C6H12O6) and O2.
6CO2 (g) + 6H2O (l) → C6H12O6 (s) + 6O2 (g)
The heat change off the reaction can be calculated as,
={(1 mol)(6 mol) }- {(6 mol) [H2O]}
=[1 1273.3 kJ + 6(0)] - [6 (-39.5 kJ) + 6 (-285.840 kJ)]
= 2802.74 or 2802.7 kJ
Thus the balanced equation can be written as,
6CO2 (g) + 6H2O (l) → C6H12O6 (s) + 6O2 (g) = 2802.7 kJ for 1.00 mol of glucose.
Answer:
C) in either position
Explanation:
There are two kinds of membrane protein:
a) Integral proteins: They have a fixed or permanent association with the membrane. They are majorly embedded in the middle layer of membrane. A kind of integral proteins are transmembrane proteins, they can cross the membrane and are path for transport of ions or molecule in and out cell.
b) Peripheral proteins: The are confined to the surface of membrane and are boned with ionic interactions. they are more in number as compared to integral proteins.
Answer:
403.176
Explanation:
I hope that the right answer.
Answer:
Moles of NaOH that reacted: 
Explanation:
During the titration, all moles of NaOH added in the solution, react with the acetylsalicylic acid neutralizing each other.
The titration required 15.62 ml (0.01562 L) of the 0.1052 M NaOH solution. The moles of NaOH in that volume are:

