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likoan [24]
3 years ago
8

Help please. Which mass of urea, CO(NH2)2, contains the same mass of nitrogen as 101.1 g of potassium nitrate?

Chemistry
1 answer:
Masja [62]3 years ago
6 0
Did u mean mass of potassium nitrate or the mass of nitrogen in potassium nitrate

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The part in the middle with a coil of wire wrapped around a metal shaft is part of an electric motor. What is it?
evablogger [386]

Answer:

  rotor

Explanation:

The part of the motor being pointed to is called the <em>rotor</em>.

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Methane is the chemical that is most abundant in natural gas.<br> a. True<br> b. False
aliya0001 [1]
<span>a. True. Methane is the chemical that is most abundant in natural gas. </span>

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Sulfur dioxide, SO2(g), can react with oxygen to produce sulfur trioxide, SO3(g), by the following reaction
WITCHER [35]

Answer:

The heat produced is -15,1kJ

Explanation:

For the reaction:

2SO₂+O₂ → 2SO₃

The enthalpy of reaction is:

ΔHr = 2ΔHf SO₃ - 2ΔHf SO₂

As ΔHf SO₃ = -395,7kJ and ΔHf SO₂ = -296,8kJ

<em>ΔHr = -197,8kJ</em>

Using n=PV/RT, the moles of reaction are:

n = \frac{1,00atm*3,75L}{0,082atmL/molK*298,15K} = <em>0,153 moles of reaction</em>

As 2 moles of reaction produce -197,8kJ of heat, 0,153moles produce:

0,153mol×\frac{-197,8kJ}{2mol} = <em>-15,1kJ</em>

<em></em>

I hope it helps!

8 0
3 years ago
*14.<br> How many atoms of sulfur are in 0.75 moles of carbon disulfide?
Sedbober [7]
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3 years ago
Propane gas, C3H8, is sometimes used as a fuel. In order to measure its energy output as a fuel a 1.860 g sample was combined wi
lisov135 [29]

Answer:

The heat of the reaction is 105.308 kJ/mol.

Explanation:

Let the heat released during reaction be q.

Heat gained by water: Q

Mass of water ,m= 1kg = 1000 g

Heat capacity of water ,c= 4.184 J/g°C

Change in temperature = ΔT = 26.061°C - 25.000°C=1.061 °C

Q=mcΔT

Heat gained by bomb calorimeter =Q'

Heat capacity of bomb calorimeter ,C= 4.643 J/g°C

Change in temperature = ΔT'= ΔT= 26.061°C - 25.000°C=1.061 °C

Q'=CΔT'=CΔT

Total heat released during reaction is equal to total heat gained by water and bomb calorimeter.

q= -(Q+Q')

q = -mcΔT - CΔT=-ΔT(mc+C)

q=-1.061^oC(1000 g\times 4.184J/g^oC+4.643 J/^oC )=-4,444.15J=-4.444 kJ

Moles of propane =\frac{1.860 g}{44 g/mol}=0.0422 mol

0.0422 moles of propane on reaction with oxygen releases 4.444 kJ of heat.

The heat of the reaction will be:

\frac{4.444 kJ}{0.0422 mol}=105.308 kJ/mol

3 0
3 years ago
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