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kolbaska11 [484]
2 years ago
5

Which word equation represents a neutralization reaction

Chemistry
2 answers:
Vlad1618 [11]2 years ago
8 0
Base+salt > acid +alkali > neutralization i think this is the reaction
Arisa [49]2 years ago
8 0

<u>Answer:</u> The word equation for neutralization reaction is given below.

<u>Explanation:</u>

Neutralization reaction is defined as the reaction in which acid reacts with base to produce a salt and water as products. The chemical equation for this reaction follows:

HX+BOH\rightarrow BX+H_2O

where,

HX is a acid

BOH is a base

BX is the salt

H_2O is the water molecule.

The word equation for the above reaction follows:

\text{Acid }+\text{ Base}\rightarrow \text{Salt }+H_2O

Hence, the word equation for the neutralization reaction is given above.

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Consider 1-bromopropane (CH3CH2CH2Br) (a) Draw a Newman projection for the conformation in which !CH3 and !Br are anti (dihedral
KiRa [710]

Answer:

<em>Figure Attached</em>

Explanation:

a. To draw a Newman projection we draw a circle for the rare carbon and and put a dot in center of circle for the front carbon. For a dihedral angle of 180° we put the respective groups opposite to each other making an angle of 180°.

b. For a dihedral angle of 60° Just rotate the conformation of dihedral angle 180° to anti clock wise up to 120°.  

For a dihedral angle of 300° Just rotate the conformation of dihedral angle 180° to clock wise up to 120°.  

c. The lowest energy conformation is the conformation having dihedral angle 180°. Because in this conformation the bulky groups are anti to each other.

d. Conformations having dihedral angle  60° and 300° are reflection of each other.

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3 years ago
A saturated solution was formed when 5.16×10−2 L of argon, at a pressure of 1.0 atm and temperature of 25 ∘C, was dissolved in 1
liraira [26]

Answer:

The Henry's law constant for argon is k=2.11*10^{-3}\frac{ M}{atm}

Explanation:

Henry's Law indicates that the solubility of a gas in a liquid at a certain temperature is proportional to the partial pressure of the gas on the liquid.

C = k*P

where C is the solubility, P the partial pressure and k is the Henry constant.

So, being the concentration C=\frac{ngas}{V}  

where ngas is the number of moles of gas and V is the volume of the solution, you must calculate the number of moles ngas. This is determined by the Ideal Gas Law: P*V=n*R*T where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas. So n=\frac{P*V}{R*T}

In this case:

  • P=PAr= 1 atm
  • V=VAr= 5.16*10⁻² L
  • R=0.082 \frac{atm*L}{mol*K}
  • T=25 °C=298 °K

Then:

n=\frac{1 atm*5.16*10^{-2} L}{0.082 \frac{atm*L}{mol*K} *298K}

Solving:

n= 2.11 *10⁻³ moles

So: C=\frac{ngas}{V}=\frac{2.11*10^{-3} moles}{1 L} =2.11*10^{-3} \frac{moles}{L}= 2.11*10^{-3} M

Using Henry's Law and being C=CAr and P =PAr:

2.11*10⁻³ M= k* 1 atm

Solving:

k=\frac{2.11*10^{-3} M}{1 atm}

You get:

k=2.11*10^{-3}\frac{ M}{atm}

<u><em>The Henry's law constant for argon is </em></u>k=2.11*10^{-3}\frac{ M}{atm}<u><em></em></u>

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