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zhuklara [117]
2 years ago
13

You've just returned to school from spring break and all of the plants in your classroom are wilted and looking bad. What do you

think happened? Use your knowledge of plant cells to explain. Can they recover?
Chemistry
1 answer:
SpyIntel [72]2 years ago
6 0
Mzkslskkskskskksosososoowkmwnwnsnsnnsnsnsnsns
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What is the simplest formula of a compound if a sample of the compound contains 0.221 mol X, 0.442 mol Y, and 0.884 mol Z? chemP
Gnoma [55]

Answer:

XY₂Z₄

2.35 mol Z

Explanation:

A sample of the compound contains 0.221 mol X, 0.442 mol Y, and 0.884 mol Z. We can find the simplest formula (empirical formula) by <em>dividing all the numbers of moles by the smallest one</em>.

X: 0.221/0.221 = 1

Y: 0.442/0.221 = 2

Z: 0.884/0.221 = 4

The simplest formula is XY₂Z₄.

The molar ratio of X to Z is 1:4. The moles of Z in a sample that contained 0.588 moles of X is:

0.588 mol X × (4 mol Z/1 mol X) = 2.35 mol Z

6 0
3 years ago
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Name the bonds found between amino acids in a polypeptide chain
Mekhanik [1.2K]

Answer:

<em><u>Primary Structure: Amino Acids Are Linked by Peptide Bonds to Form Polypeptide Chains. Proteins are linear polymers formed by linking the α-carboxyl group of one amino acid to the α-amino group of another amino acid with a peptide bond (also called an amide bond).</u></em>

Explanation:

<em><u>hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u> you</u></em>

8 0
3 years ago
How many milliliters are in one milligram?
mariarad [96]
1 milliliters in one milligram.
8 0
3 years ago
The mass of 2.50 moles of calcium fluoride is ____ grams
Vesna [10]

Answer:

195.187016

Explanation:

3 0
3 years ago
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In going from room temperature (25 C) to 10 C above room temperature, the rate of reaction doubles. Calculate the activation ene
Sauron [17]

Answer:

Ea=5.29 × 10⁴ J/mol

Explanation:

In going from 25 °C (298 K) to 35 °C (308 K), the rate of the reaction doubles. Since the rate of the reaction depends on the rate constant (k), this implies that the rate constant doubles. We can find the activation energy (Ea) using the two-point form of the Arrhenius equation.

ln\frac{k_{2}}{k_{1}} =\frac{-Ea}{R} .(\frac{1}{T_{2}}-\frac{1}{T_{1}})\\ln\frac{2k_{1}}{k_{1}}=\frac{-Ea}{8.314J/K.mol}.(\frac{1}{308K}-\frac{1}{298K} )\\Ea=5.29 \times 10^{4} J/mol

8 0
3 years ago
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