A 684.6 mL sample of carbon dioxide was heated to 387 K. If the volume of the carbon dioxide sample at 387 K is 933.9 mL, what w
1 answer:
According to Charle's law equation, the volume of a sample of carbon dioxide will be 684.6 mL and the temperature will be 283.60 K.
<h3>Charle's law equation</h3>According to Charles' Law, the volume of a gas container with a certain amount of gas within is precisely proportional to the temperature when the pressure is constant.
<h3>Calculation:</h3> = 684.6 mL
= 933.9 mL
= ?
= 387 K
Using Charle's law equation
According to Charle's law equation, the temperature at 684.6 mL volume was 283.60 K.
For more information about Charle's law equation here
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Answer:
A) 6.48 g of OF₂ at the anode.
Explanation:
The gas OF₂ can be obtained through the oxidation of F⁻ (inverse reaction of the reduction presented). The standard potential of the oxidation is the opposite of the standard potential of the reduction.
H₂O(l) + 2 F⁻(aq) → OF₂(g) + 2 H⁺(aq) + 4 e⁻ E° = -2.15 V
Oxidation takes place in the anode.
We can establish the following relations:
- 1 Faraday is the charge corresponding to 1 mole of e⁻.
- 1 mole of OF₂ is produced when 4 moles of e⁻ circulate.
- The molar mass of OF₂ is 54.0 g/mol.
The mass of OF₂ produced when 0.480 F pass through an aqueous KF solution is: