Question

A 684.6 mL sample of carbon dioxide was heated to 387 K. If the volume of the carbon dioxide sample at 387 K is 933.9 mL, what was its temperature at 684.6 mL

Answer 1

According to Charle's law equation, the volume of a sample of carbon dioxide will be 684.6 mL and the temperature will be 283.60 K.

Charle's law equation

According to Charles' Law, the volume of a gas container with a certain amount of gas within is precisely proportional to the temperature when the pressure is constant.

Calculation:

$V_{1}$ = 684.6 mL

$V_{2}$ = 933.9 mL

$T_{1}$ = ?

$T_{2}$ = 387 K

Using Charle's law equation

$\frac{684.6}{T_{1} } = \frac{933.9}{387}$

$T_{1} = \frac{2,64,862.8}{933.9}$

$T_{1} = 283.60 K$

According to Charle's law equation, the temperature at 684.6 mL volume was 283.60 K.

For more information about Charle's law equation here

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