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romanna [79]
2 years ago
9

On Darwin's tree of life, organisms at the base of

Chemistry
2 answers:
bazaltina [42]2 years ago
7 0
The correct answer is part A
masya89 [10]2 years ago
3 0
B - Evolve into the closest species on the tree’s trunk
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PLEASE HELP ME ASAP!!! <br> I need the answer to #9. If you can show work please do.
scoundrel [369]

The correct answer would be 32/16s


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3 years ago
Which of the following is a galvanic cell?
Gemiola [76]

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i think Aluminum (Al) oxidized, zinc(Zn) reduced

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3 years ago
Sugar when dissolved into water, propose whether the compound forms atoms, molecules or lattices. Justify you answer
kirza4 [7]

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atoms

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6 0
3 years ago
Which is a type of tectonic plate boundary?
UNO [17]
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5 0
3 years ago
Three samples of the same metal are weighed and their masses are found to be 44.40 g, 40.58 g, and 38.35 g. The corresponding vo
lidiya [134]

The density of a material is the mass of the material per unit volume. Here the weight of the same metal is 44.40g, 40.58g and 38.35g having volume 4.8 mL, 4.7 mL and 4.2 mL respectively. Thus the density of the metal as per the given data are, \frac{44.40}{4.8} = 9.25g/mL, \frac{40.58}{4.7} = 8.634g/mL and \frac{38.35}{4.2} = 9.130g/mL respectively.

The equation of the standard deviation is √{∑(x  - \frac{}{x})÷N}

Now the mean of the density is {(9.25 + 8.634 + 9.130)/3} = 9.004 g/mL.

The difference of the density of the 1st metal sample (9.25-9.004) = 0.246 g/mL. Squaring the value = 0.060.

The difference of the density of the 2nd metal sample (9.004-8.634) =0.37 g/mL. Squaring the value = 0.136.

The difference of the density of the 3rd metal sample (9.130-9.004) = 0.126 g/mL. Squaring the value 0.015.

The total value of the squared digits = (0.060 + 0.136 + 0.015) = 0.211. By dividing the digit by 3 we get, 0.070. The standard deviation will be \sqrt{0.070}=0.265. Thus the standard deviation of the density value is 0.265g/mL.  

5 0
3 years ago
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