Answer:
Alcohol and water.
Explanation:
Alcohol and water is a homogenous mixture. because these two liquids are soluble, miscible in all composition. A homogenous mixture is a solution that has equal composition of its components.
Irregular mixing of two liquid components have different refractive indexes. At a high temperature, it can become inhomogenous spontaneously.
A solution is a type of homogenous mixture which composed of two or more substances. In a mixture a solute is a substance, dissolves in other substance that is solvents like alcohol and water, alcohol is solute and water is a solvent.
Answer: Small groups of atoms that are attached to larger molecules, giving the specific chemical properties, are called functional groups.
explanation: Functional groups are groups of atoms in a molecule that possess the same chemical feature every time it appears in several compounds. There are various types of functional groups and they have the tendency to react in definite ways. Examples include; the ether functional group (consists of an oxygen atom that forms single bonds with two carbon atoms),the alcohol functional group (consists of an oxygen atom that is bonded to one hydrogen atom and one carbon atom), and the amine functional group (consists of a nitrogen atom bonded to some combination of carbons and hydrogens).
That would be A.
2.5*2*10^(10-7)=5*10^3
Answer:
a) 
b) 
Explanation:
Equation of reaction:
Initial pressure 3 1 0
Pressure change 2P 1P 2P
Total pressure = (3-2P) + (1-P) + (2P)
Total Pressure = 3.75 atm
(3-2P) + (1-P) + (2P) = 3.75
4 - P = 3.75
P = 4 - 3.75
P = 0.25 atm
Let us calculate the pressure of each of the components of the reaction:
Pressure of XO2 = 3 - 2P = 3 - 2(0.25)
Pressure of XO2 =2.5 atm
Pressure of O2 = 1 - P = 1 -0.25
Pressure of O2 = 0.75 atm
Pressure of XO3 = 2P = 2 * 0.25
Pressure of XO3 = 0.5 atm
From the reaction, equilibrium constant can be calculated using the formula:
![K_{p} = \frac{[PXO_{3}] ^{2} }{[PXO_{2}] ^{2}[PO_{2}] }](https://tex.z-dn.net/?f=K_%7Bp%7D%20%3D%20%5Cfrac%7B%5BPXO_%7B3%7D%5D%20%5E%7B2%7D%20%7D%7B%5BPXO_%7B2%7D%5D%20%5E%7B2%7D%5BPO_%7B2%7D%5D%20%7D)
Standard free energy:
b) value of k−1 at 27 °C, i.e. 300K
