The ratio 21:14 when divided by 7 on each side, is the smallest ratio that has the same value as 21:14. this becomes 3:2
then multiply both sides by a few different numbers on both sides each ,
for example, 3:2 is the same as
6:4 (3:2 times 2)
9:6 (3:2 times 3)
12:8 (3:2 times 4)
15:10 (3:2 times 5) and so on
the ratio of the right number I
divided by the left on all of them is 1.5
so,
14/10 equals 1.4 (nope)
8/4 equals 2 (nope)
9/6 equals 1.5 (yay)
12/21 equals 0.57 (Lol)
So your answer is 9:6
Answer:
The area is 161
Step-by-step explanation:
brainliest?
Answer:
2 and -5
Step-by-step explanation:
x2 + 3x - 10 = 0
Factors of -10 include, -2 and 5
so now we have to factor
(x-2)(x+5)
so x can equal 2 and -5
Answer:
The coordinates of P' are (4.8,-4.8).
Step-by-step explanation:
The rule of dilation 
represent the dilation with scale factor 2.4 and center at origin.
If the scale factor of the dilation is k and the center is (0,0), then
Since the scale factor is 2.4, therefore
From the given figure it is noticed that the coordinates of P are (2,-2). The coordinates of P' are
Therefore the coordinates of P' are (4.8,-4.8).
Suppose we wish to determine whether or not two given polynomials with complex coefficients have a common root. Given two first-degree polynomials a0 + a1x and b0 + b1x, we seek a single value of x such that
Solving each of these equations for x we get x = -a0/a1 and x = -b0/b1 respectively, so in order for both equations to be satisfied simultaneously we must have a0/a1 = b0/b1, which can also be written as a0b1 - a1b0 = 0. Formally we can regard this system as two linear equations in the two quantities x0 and x1, and write them in matrix form as
Hence a non-trivial solution requires the vanishing of the determinant of the coefficient matrix, which again gives a0b1 - a1b0 = 0.
Now consider two polynomials of degree 2. In this case we seek a single value of x such that
Hope this helped, Hope I did not make it to complated
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