Answer:
Half of the moon or 50%
Explanation:
The first quarter phase of the moon is when the Sun illuminates the half part of the moon while the other half rest in darkness.
In the first quarter phase of the moon, the illumination on the moon surface keeps on rising.
When the new moon appear, there is no illumination while the illumination is 100 % on Full moon.
For the phases of crescent moon, it ranges from 0 - 50% and then for gibbous phase, the range of the illumination is from 50-100%from new
Newton's 2nd law of motion.
kinds,
External Force
Surface Tension
Pseudo Force
Frictional Force
Viscous Force
Buoyancy
Answer:
185 A
Explanation:
In order for the rod to float above the ground, the magnetic force between the two rods must be equal to the weight of the floating rod.
So we can write:
where the term on the left is the magnetic force and the term on the right is the weight, and where:
is the vacuum permeability
is the current in the two rods (they carry the same current)
is the length of the floating rod
r is the distance between the rods
is the mass of the floating rod
g is the acceleration due to gravity
Here we have:
Therefore, solving for I, we find:
Complete question:
Two parallel 3.0-meter long wires conduct current. The current in the top wire is 12.5 A and flows to the right. The top wire feels a repulsive force of 2.4 x 10^-4 N created by the interaction of the 12.5 A current and the magnetic field created by the bottom current (I). Find the magnitude and direction of the bottom current, if the distance between the two wires is 40cm.
Answer:
The bottom current is 12.8 A to the right.
Explanation:
Given;
length of the wires, L = 3.0 m
current in the top wire, I₁ = 12.5 A
repulsive force between the two wires, F = 2.4 x 10⁻⁴ N
distance between the two wires, r = 40 cm = 0.4 m
The repulsive force between the two wires is given by;
Where;
I₂ is the bottom current
The direction of the bottom current must be in the same direction as the top current since the force between the two wires is repulsive.
Therefore, the bottom current is 12.8 A to the right.