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lilavasa [31]
3 years ago
14

How does a resistor affect an electrical circuit?

Physics
2 answers:
Klio2033 [76]3 years ago
5 0

Answer:

D.

It reduces the rate at which electrons flow.

Vanyuwa [196]3 years ago
3 0

Answer:

D

Explanation:

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3. Una cuerda de guitarra tiene 60 cm de longitud y una masa de 0.05 kg de masa. Si se tensiona mediante una fuerza de 20 N. La
jok3333 [9.3K]

Answer:

f1 = 12.90 Hz

Explanation:

To calculate the first harmonic frequency you use the following formula for n = 1:

f_n=\frac{n}{2L}\sqrt{\frac{T}{M/L}}

f_1=\frac{1}{2L}\sqrt{\frac{T}{M/L}}    ( 1 )

It is necessary that the unist are in meters, then you have:

L: length of the string = 60cm = 0.6m

M: mass of the string = 0.05kg

T: tension on the string = 20 N

you replace the values of L, M and T in the expression (1) for getting f1:

f_1=\frac{1}{2(0.6m)}\sqrt{\frac{20N}{0.05kg/0.6m}}=12.90\ Hz

Hence, the first harmonic has a frequency of 12.90 Hz

4 0
3 years ago
If there are two photons with different energies, the one that has a higher energy (a) has the higher frequency (b) has the high
kozerog [31]

Answer:

(a) has the highest frequency

Explanation:

E = hf...where E(is the energy of a photon);h(is the planck's constant) and f is the frequency of the photon

Whereby this formula shows us that energy of a photon is directly proportional to its frequency

So hence if the energy is high then the frequency of the photon is also high

3 0
3 years ago
If the potential difference across the bulb in a camping lantern is 9.0 V, what is the
Gre4nikov [31]

Answer:

9V

Explanation:

The potential difference across the terminal as the same and thats because we are assuming that the source has no internal resistance.

Internal resistance are usually little resistances in the supply.

4 0
3 years ago
If the primary of a transformer were connected to a dc power source,
QveST [7]

Answer:

D. only briefly while being connected or disconnected.

Explanation:

As we know that transformer works on the principle of mutual inductance

here we know that as per the principle of mutual inductance when flux linked with the primary coil charges then it will induce EMF in secondary coil

So here when AC source is connected with primary coil then it will give output across secondary coil because AC source will have change in flux with time.

Now when we connect DC source across primary coil then it will not induce any EMF across secondary coil because DC source is a constant voltage source in which flux will remain constant always

So here in DC source the EMF will only induce at the time of connection or disconnection when flux will change in it while rest of the time it will give ZERO output

so correct answer will be

D. only briefly while being connected or disconnected.

8 0
3 years ago
if the efficiency of an electric furnace is 96%, then 96% of the input energy is transformed into thermal energy. what is the ot
Nonamiya [84]
It is wasted, most likely as light, in this case, or it is lost during the transport of electricity.
5 0
3 years ago
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