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Alex787 [66]
3 years ago
13

g For each of the following cases, indicate whether the first entity is greater than, less than or equal to the second entity. W

rite 'G' for greater, 'L' for less and 'E' for equal (The letters must be in uppercase) Enthalpy of combustion of a fuel at STP Enthalpy of combustion of the same fuel at 20°C Enthalpy of formation of methane at STP Enthalpy of formation of methane at 1000 K and 100 kPa Enthalpy of combustion of gas propane with stoichiometric air Enthalpy of combustion of gas propane with 150% theoretical air. Adiabatic Flame Temperature of combustion reaction of liquid butane with equivalence ratio of 1.5 Adiabatic Flame Temperature

Chemistry
1 answer:
Marianna [84]3 years ago
7 0

Answer:

Explanation

check the solution in the attached

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In trying to control fall armyworms in crops, an Agriculture extension officer applied cypermethrin which was prepared by dissol
sveta [45]

Answer:

Mole fraction for C₂₂H₁₉Cl₂NO₃ = 0.0086

Explanation:

Mole fraction remains a sort of concentration. It indicates:

moles of solute / (moles of solute + moles of solvent)

Moles of solute / Total moles.

Solute: Cypermethrin → C₂₂H₁₉Cl₂NO₃

Solvent: Water (PM = 18g/mol)

We calculate moles from solvent: 1000g /18 g/mol = 55.5 moles

We calculate PM for C₂₂H₁₉Cl₂NO₃

12g/mol . 22 + 1g/mol . 19 + 35.45 g/mol . 2+ 14g/mol + 16g/mol . 3 = 416 g/m

Moles of solute: 200 g / 416g/mol = 0.481 moles

Total moles: 0.481 + 55.5 = 55.98 moles

Mole fraction for C₂₂H₁₉Cl₂NO₃ = 0.481 moles / 55.98 moles = 0.0086

8 0
3 years ago
3) In the reaction below, how many grams of carbon dioxide are produced when iron III
Yanka [14]
<h3>Answer:</h3>

132.03 g

<h3>Explanation:</h3>

<u>We are given;</u>

  • The equation for the reaction as;

Fe₂O₃ + 3CO → 2Fe + 3CO₂

  • Molar masses of CO and CO₂ as 28.01 g/mol and 44.01 g/mol respectively
  • Mass of CO as 84 grams

We are required to calculate the mass of CO₂ that will produced.

<h3>Step 1: Calculate the number of moles of CO</h3>

Moles = Mass ÷ Molar mass

Molar mass of CO = 28.01 g/mol

Therefore;

Moles of CO = 84 g ÷ 28.01 g/mol

                     = 2.9989 moles

                    = 3.0 moles

<h3>Step 2: Calculate the number of moles of CO₂</h3>
  • From the reaction, 3 moles of CO reacts to produce 3 moles of CO₂
  • Therefore; the mole ratio of CO to CO₂ is 1 : 1
  • Hence; Moles of CO = Moles of CO₂

Moles of CO₂ = 3.0 Moles

But; mass = Moles × molar mass

Thus, mass of CO₂ = 3.0 moles × 44.01 g/mol

                                = 132.03 g

Hence, the mass of CO₂ produced from the reaction is 132.03 g

3 0
4 years ago
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