g For each of the following cases, indicate whether the first entity is greater than, less than or equal to the second entity. W
rite 'G' for greater, 'L' for less and 'E' for equal (The letters must be in uppercase) Enthalpy of combustion of a fuel at STP Enthalpy of combustion of the same fuel at 20°C Enthalpy of formation of methane at STP Enthalpy of formation of methane at 1000 K and 100 kPa Enthalpy of combustion of gas propane with stoichiometric air Enthalpy of combustion of gas propane with 150% theoretical air. Adiabatic Flame Temperature of combustion reaction of liquid butane with equivalence ratio of 1.5 Adiabatic Flame Temperature
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Explanation:
It is known that rate of effusion of gases are inversely proportional to the square root of their molar masses.
And, half of the helium (1.5 L) effused in 24 hour. So, the rate of effusion of He gas is calculated as follows.
= 0.0625 L/hr
As, molar mass of He is 4 g/mol and molar mass of is 32 g/ mol.
Now,
= 2.83
or, rate of
=
Rate of = 0.022 L/hr.
This means that 0.022 L of gas effuses in 1 hr
So, time taken for the effusion of 1.5 L of gas is calculated as follows.
= 68.18 hour
Thus, we can conclude that 68.18 hours will it take for half of the oxygen to effuse through the membrane.