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DaniilM [7]
3 years ago
5

A balloon that had a volume of 3.50 L at 25.0°C is placed in a hot room at 40.0°C. If the pressure remains constant at 1.00 atm,

what is the new volume of the balloon in the hot room? Use mc005-1.jpg.
Chemistry
2 answers:
Elina [12.6K]3 years ago
7 0

Using charles law, this would equal 3.68 L

belka [17]3 years ago
6 0

To solve this we assume that the gas inside the balloon is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

T1 / V1 = T2 / V2

V2 = T2 x V1 / T1

V2 = 313.15 x 3.50 / 298.15

<span>V2 = 3.68 L</span>

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88,88 % de O y 11,11 % de H

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<h3>88,88 % de O y 11,11 % de H</h3>
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