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DaniilM [7]
3 years ago
5

A balloon that had a volume of 3.50 L at 25.0°C is placed in a hot room at 40.0°C. If the pressure remains constant at 1.00 atm,

what is the new volume of the balloon in the hot room? Use mc005-1.jpg.
Chemistry
2 answers:
Elina [12.6K]3 years ago
7 0

Using charles law, this would equal 3.68 L

belka [17]3 years ago
6 0

To solve this we assume that the gas inside the balloon is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

T1 / V1 = T2 / V2

V2 = T2 x V1 / T1

V2 = 313.15 x 3.50 / 298.15

<span>V2 = 3.68 L</span>

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A chemist prepares a solution of iron(III) bromide (FeBr3) by measuring out 41.1 mg of FeBr3 into a 50. mL volumetric flask and
allsm [11]

Answer: The molarity of Br^- anions in the chemist's solution is 0.0084 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute

V_s = volume of solution in ml

moles of FeBr_3 = \frac{\text {given mass}}{\text {Molar mass}}=\frac{0.0411g}{295.6g/mol}=0.00014mol

Now put all the given values in the formula of molality, we get

Molarity=\frac{0.00014\times 1000}{50}=0.0028

As 1 mole of FeBr_3 gives = 3 moles of Br^-

0.0028 moles of FeBr_3 gives = \frac{3}{1}\times 0.0028=0.0084 moles of Br^-

Thus the molarity of Br^- anions in the chemist's solution is 0.0084 M

5 0
3 years ago
An aqueous solution of orthophosphoric acid, H3PO4, has a measured density of 1.2089 g mL-1 and is 5.257 molal. The solution is
AleksandrR [38]

Answer:

In one liter of solution, there are 4.194 moles of H₃PO₄

Explanation:

A molal solution contains 1 mole of solute in 1 Kg of solvent.

A  aqueous 5.257 molal solution of H₃PO₄ will contain 5.257 moles of  H₃PO₄ in 1 Kg or 1000 g of water .

Molar mass of H₃PO₄ = 98 g/mol

Therefore mass of H₃PO₄ = number of moles * molar mass

mass of H₃PO₄ = 5.257 mol * 98 g/mol = 515.2 g

mass of solution = mass of solute + mass of solvent

mass of solution = 515.2 + 1000 = 1515.2 g

Volume of solution = mass of solution / density of solution

Volume of solution = 1515.2 / 1.2089 = 1253.4 mL

Molarity of solution = number of moles / volume (L)

Molarity of solution = 5.257 / 1.2534 L = 4.194 mol/L

Therefore, in one liter of solution, there are 4.194 moles of H₃PO₄

4 0
3 years ago
2. How many atoms are in 5.6 moles of Na? Answer:___3.2 E 24 atoms of Na​
jeyben [28]

Answer:

5.6\frac{6.02*10^{23} }{1} = 3.4 X 10^{24}

Explanation:

the correct answer to it is 3.4 instead of 3.2. I got 3.4 from rounding it from 3.37.

8 0
3 years ago
Consider the system at equilibrium. 2 H 2 ( g ) + S 2 ( g ) − ⇀ ↽ − 2 H 2 S ( g ) How will increasing the concentration of S 2 s
borishaifa [10]

Answer:

1) the balance will shift to the right

2) the balance will shift to the left

3) There will be no effect on the position of the equilibrium.

Explanation:

Step 1: Data given

The Principle of Le Chatelier says 'If the concentration of one of the reaction partners changes, the balance will shift to counteract that concentration change.

Step 2: The balanced equation

2H2(g) + S2(g) ⇆ 2H2S(g)

Step 3: How will increasing the concentration of S2 shift the equilibrium?

If the S2 concentration is increased, the system will attempt to undo that change in concentration by shifting the balance to the right, and so the H2S concentration will increase.

Step 4: How will increasing the concentration of H2S shift the equilibrium?

If the H2S concentration is increased, the system will attempt to undo that change in concentration by shifting the balance to the left, and so the H2 and S2 concentration will increase.

Step 5: How will adding a catalyst shift the equilibrium?

Reactions can be sped up by the addition of a catalyst.

In the presence of a catalyst, both the forward and reverse reaction rates will speed up equally, thereby allowing the system to reach equilibrium faster.

Adding a catalyst makes absolutely no difference to the position of equilibrium.

6 0
4 years ago
In covalent bonding, nonmetal atoms _____ electrons that typically result in filled s and p orbitals. A) lose B) gain C) share D
Mama L [17]

Nonmetal atoms would share electrons in a covalent bonding.

Hope this helped! :D

3 0
3 years ago
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