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Brrunno [24]
3 years ago
15

This table compares magnitude and depth of four earthquakes occurring between 1955 - 2017. The surface changes that occur as a r

esult of earthquakes begin in Earth's crust. What conclusion can be drawn about earthquake activity within Earth's crust based on the data shown?
A) Earthquake depth has continuously increased throughout the past century.


B) Higher-magnitude earthquakes do not always happen deeper in Earth's crust.


C) The higher an earthquake's magnitude, the deeper in Earth's crust it occurs.


D) Earthquake magnitude has continuously decreased throughout the past century.

Chemistry
1 answer:
torisob [31]3 years ago
3 0

Answer:

The correct answer is option B) "Higher-magnitude earthquakes do not always happen deeper in Earth's crust".

Explanation:

The table shows data of magnitude and depth of earthquakes that occurred at different time and at different locations. By analyzing the data we can conclude that higher-magnitude earthquakes do not always happen deeper in Earth's crust. At first glance we can thought that higher-magnitude earthquakes occur at high depth. However, the earthquake of Michoacan have a higher-magnitude than the earthquake of Alexandria (8 and 6.3, respectively), and the earthquake of Michoacan occurred at 12 miles of depth, while the earthquake of Alexandria occurred at 15 miles of depth.

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3 years ago
A solution made by dissolving 33 mg of insulin in 6.5 mL of water has an osmotic pressure of 15.5 mmHg at 25°C. Calculate the mo
Liula [17]

<u>Answer:</u> The molar mass of the insulin is 6087.2 g/mol

<u>Explanation:</u>

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=iMRT

Or,

\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT

where,

\pi = osmotic pressure of the solution = 15.5 mmHg

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (insulin) = 33 mg = 0.033 g   (Conversion factor: 1 g = 1000 mg)

Volume of solution = 6.5 mL

R = Gas constant = 62.364\text{ L.mmHg }mol^{-1}K^{-1}

T = temperature of the solution = 25^oC=[273+25]=298K

Putting values in above equation, we get:

15.5mmHg=1\times \frac{0.033\times 1000}{\text{Molar mass of insulin}\times 6.5}\times 62.364\text{ L.mmHg }mol^{-1}K^{-1}\times 298K\\\\\text{molar mass of insulin}=\frac{1\times 0.033\times 1000\times 62.364\times 298}{15.5\times 6.5}=6087.2g/mol

Hence, the molar mass of the insulin is 6087.2 g/mol

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3 years ago
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