Answer:
pH of the final solution = 3.8
Explanation:
Concentration of NaF = 
molar
= 0.3 molar
NaF → Na⁺ + F⁻
HF ⇆ H⁺ + F⁻
- NaF is strong electrolyte so completely ionized but HF weak acid not completely ionized.
- Since F⁻ is common ion here
according to common ion effect dissociation of weak acid decreases.
Ka = ![\frac{[H]^{+}[F]^{-} }{[HF]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BH%5D%5E%7B%2B%7D%5BF%5D%5E%7B-%7D%20%20%7D%7B%5BHF%5D%7D)
⇒ [H⁺] = ![\frac{K_{a} [HF]}{[F]^{-} }](https://tex.z-dn.net/?f=%5Cfrac%7BK_%7Ba%7D%20%5BHF%5D%7D%7B%5BF%5D%5E%7B-%7D%20%7D)
...............(1)
{Ka of HF = 3.5 x 10⁻⁴} & Concentration of HF = 30 x 4 x 10⁻³ = 0.12 molar
from equation 1
⇒ [H⁺] = 
[Concentration of F⁻ ≡ Concentration of NaF]
⇒ [H⁺] = 0.00014
⇒pH = - log 0.00014 = 3.85
Answer:
Zero-Nine
Explanation:
this is becasue these numbers are rather small and if you plug these numbers into an equation you will most likely get 0.
Answer:
0.2298kg of Al
Explanation:
From the equation of reaction
3 moles of Al (81g) is required to mix with 3 moles of NH4ClO4 (352.5g)
Mass of Al required in the fuel mixture for every kilogram (1000g) of NH4ClO4 = 1000×81/352.5 = 229.8g = 229.8/1000 = 0.2298kg
Answer:
NaCl = 58.44g/mol
Explanation:
Na = 22.99/58.44 × 100 = 39.33%
Cl = 35.45/58.44 × 100 = 60.66%
The pressure increases if the volume decreases
