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Yuri [45]
3 years ago
14

Help me solve. Djdjdjfjdkdjdjdkdkckckdkck

Chemistry
2 answers:
liraira [26]3 years ago
8 0
Hello there (Henry?). The answer would be 55. You have to add them. Substances can't simply disappear ;)
ivanzaharov [21]3 years ago
4 0
I would believe it to be 55g. A -> B YIELDS AB. So, 10g + 45g = 55g.
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Calculate a reasonable amount (mass in g) of your unknown acid to use for a titration. You will want about 30 mL of titrant to g
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Answer:

"0.60 g" is the appropriate solution.

Explanation:

The given values are:

Volume of base,

= 30 ml

Molarity of base,

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Molar mass of acid,

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As we know,

⇒  Molarity=\frac{Number \ of \ moles \ of \ base}{Number \ of \ solution}

On substituting the values, we get

⇒           0.05=\frac{Number \ of \ moles \ of \ base}{30\times 10^{-3}}

⇒  Number \ of \ moles \ of \ base=0.05\times 30\times 10^{-3}

⇒                                             =1.5\times 10^{-3}  

hence,

⇒  Moles \ of \ acid=\frac{Mass \ of \ acid}{Molar \ mass \ of \ acid}

On substituting the values, we get

⇒  1.5\times 10^{-3}=\frac{Mass \ of \ acid}{400}

⇒  Mass \ of \ acid=1.5\times 10^{-3}\times 400

⇒                         =0.60 \ g

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