<span>The most significant factor that controls the development of soil is B. climate. Depending on what the climate and the weather are like in a particular area, the soil will be either developed and healthy and fertile, or it won't if the conditions are too harsh. If the weather is nice, usually the soil will form which will be suitable for crops and agriculture, but if it's too hot or too cold, the soil won't be used for such things as it won't be fertile.</span>
The sulfur and nitrogen compounds in smog combine with water to form Acid Rain. Acid rain is harmful to the environment and infrastructure because of its aidic components.
Answer:
-56.1kJ/mol
Explanation:
The reaction between HCl and NaOH is:
NaOH + HCl → NaCl + H₂O + ΔH
<em>Where ΔH is heat change in the reaction.</em>
<em />
As the temperature of the solution increases, the heat is released and ΔH < 0
The heat released in the reaction is obtained using coffe-cup calorimeter equation:
Q = C×m×ΔT
<em>Where Q is heat</em>
<em>C is specific heat of the solution (4.184J/g°C)</em>
<em>m is mass of solution: Assuming density = 1g/mL, 100mL of solution = 100g</em>
<em>And ΔT is change in temperature (13.4°C)</em>
<em />
Replacing:
Q = C×m×ΔT
Q = -4.184J/g°C×100g×13.4
Q = -5606.6J
Now, in the reaction you have:
<em>Moles HCl:</em>
0.050L * (2.2mol/L) = 0.11 moles
<em>Moles NaOH:</em>
0.050L * (2.0mol/L) = 0.1 moles
That means the moles of reaction are 0.1 moles, and heat change in the chemical reaction is:
5606.6J / 0.1 mol = 56066J =
<h3>-56.1kJ/mol</h3>
<em />
The product of electrolysis : Al at cathode and Cl₂(chlorine) at anode
<h3>Further explanation</h3>
Given
Aluminum chloride compound
Required
The product of electrolysis
Solution
The rule :
The reaction at the cathode(the negative pole) :
1. the reduced active metal is water, other than that the metal will be reduced
2. H⁺ of the acid will be reduced
The reaction at the anode((the positive pole) :
1. if the electrodes are not inert then the metal is oxidized
2. If inert then:
a. OH⁻ from the base will be oxidized
b. The halogen metal will oxidize
In the electrolysis of molten AlCl₃ with an inert electrode, the cation will be reduced at the cathode and the anion will be oxidized at the anode
Cathode : Al³⁺ + 3e⁻ ⇒ Al(s)
Anode : 2Cl⁻⇒Cl₂(g) + 2e⁻
