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Elis [28]
3 years ago
13

A string fixed at both ends has a length of 1 m. With a frequency of 44 kHz (fourth overtone), standing waves are produced. Whic

h harmonics will be audible to a human? (The frequency range for human hearing is 20 Hz to 20 kHz)
Physics
1 answer:
Taya2010 [7]3 years ago
6 0
The frequency of the nth-harmonic of a standing wave is an integer multiple of the fundamental frequency of the string, according to:
f_n = nf_1 (1)
where f_1 is the fundamental frequency.

We know the frequency of the 4th overtone (44 kHz), which corresponds to the 5th harmonic (n=5). Therefore, we can find the fundamental frequency of the string by rearranging equation (1):
f_1 =  \frac{f_5}{5}= \frac{44 kHz}{5}=8.8 kHz

And by using the same formula we can find the following harmonics:
f_2 = 2 f_1 = 2 \cdot 8.8 kHz =17.6 kHz
f_3 = 3f_1 = 3 \cdot 8.8 kHz =26.4 kHz
f_4 = 4 f_1 = 4 \cdot 8.8 kHz =35.2 kHz

And since the audible range for human goes from 20 Hz to 20 kHz, we see that onlyt the first two harmonics (8.8 kHz and 17.6 kHz) will be audible to a human.
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The kinetic energy in the first case is 4 times more than the second case.

Hence, option D)It is 4 times greater is the correct answer.

<h3>What is Kinetic Energy?</h3>

Kinetic energy is simply a form of energy a particle or object possesses due to its motion.

It is expressed as;

K = (1/2)mv²

Where m is mass of the object and v is its velocity.

Given that;

  • For the first case, velocity v = 16m/s
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  • Let the mass of the car be m

For the first case, kinetic energy of the car will be;

K = (1/2)mv²

K = (1/2) × m × (16m/s)²

K = (1/2) × m × 256m²/s²

K = mass × 128m²/s²

For the second case, kinetic energy of the car will be;

K = (1/2)mv²

K = (1/2) × m × (8m/s)²

K = (1/2) × m × 64m²/s²

K = mass × 32m²/s²

Comparing the kinetic energy of the car with the same mass but different velocity, we can see that the kinetic energy in the first case is 4 times more than the second case.

Hence, option D)It is 4 times greater is the correct answer.

Learn more about kinetic energy here: brainly.com/question/12669551

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ss7ja [257]

Answer:

False

Explanation:

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A common flashlight bulb is rated at 0.23 a and 2.9 v (the values of the current and voltage under operating conditions). if the
allochka39001 [22]
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2 years ago
A space station, in the form of a wheel 119 m in diameter, rotates to provide an "artificial gravity" of 2.20 m/s2 for persons w
Rina8888 [55]
<span>Well, since it's in the shape of a wheel and the person walks around the edge of it, they must have a centripetal acceleration. Since a=v^2/r you can solve for "v" using 2.20 as your "a" and 59.5 as your "r" (r=half of the diameter).
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</span></span><span> After you get "v," plugged that into T=2 pi r/ v. This will give you the 1rev per sec.
</span> T=2 pi r/ v= T=(2)*(pi)*(59.5)/(11.44)= <span> <span>32.68 rev/s
</span></span> Use dimensional analysis to get rev per min (1rev / # sec) times (60 sec/min). 
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