A Ferris Wheel, starting from rest, undergoes a constant angular acceleration of 0.033 rad/s2 to get to its final operating angu
1 answer:
Answer:
The time taken for the Ferris Wheel to get the final angular velocity is 7.27 s.
Explanation:
Given;
initial angular velocity of the Ferris Wheel, = 0
angular acceleration, α = 0.033 rad/s²
final angular velocity, = 0.24 rad/s
The time taken for the Ferris Wheel to get the final angular velocity is calculated as;
Therefore, the time taken for the Ferris Wheel to get the final angular velocity is 7.27 s.
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Answer:
8.56 m/s2
Explanation:
Using law of energy conservation while taking into account of the rotational and translation kinetic energy, when the solid cylinder rolls down the incline we have the potential energy converted to kinetic energy:
where m is the mass, is the moments of inertia of the solid cylinder
is the angular speed of the cylinder
So if you plot a liner chart of h vs and get a slope of 6.42 then that means 3/(4g) = 6.42 so
The gravitational acceleration on this planet is 8.56 m/s2
Therefore, the magnitude of magnetic field at a distance 1.10cm from the origin is 27.3mT
<u>Explanation:</u>
Given;
Number of turns, N = 1000
Inner radius, r₁ = 1cm
Outer radius, r₂ = 2cm
Current, I = 1.5A
Magnetic field strength, B = ?
The magnetic field inside a tightly wound toroid is given by B = μ₀ NI / 2πr
where,
a < r < b and a and b are the inner and outer radii of the toroid.
The magnetic field of toroid is
Substituting the values in the formula:
Therefore, the magnitude of magnetic field at a distance 1.10cm from the origin is 27.3mT