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Deffense [45]
3 years ago
12

A Ferris Wheel, starting from rest, undergoes a constant angular acceleration of 0.033 rad/s2 to get to its final operating angu

lar velocity of 0.24 rad/s. (a) How long does it take the Ferris Wheel to get to its operating angular velocity
Physics
1 answer:
vekshin13 years ago
7 0

Answer:

The time taken for the Ferris Wheel to get the final angular velocity is 7.27 s.

Explanation:

Given;

initial angular velocity of the Ferris Wheel, \omega _i = 0

angular acceleration, α = 0.033 rad/s²

final angular velocity, \omega _f = 0.24 rad/s

The time taken for the Ferris Wheel to get the final angular velocity is calculated as;

t = \frac{\omega _f - \omega _i}{\alpha} \\\\t = \frac{o.24 -0}{0.033}\\\\t = 7.27 \ s

Therefore, the time taken for the Ferris Wheel to get the final angular velocity is 7.27 s.

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Write any two important of gravitational force?
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Answer:

Explanation:

Gravitational force is important because:

1.  because of the gravitational force of the earth, the atmosphere is present around its surface, which is crucial for sustainability of life on earth

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A string under a tension of 36 N is used to whirl a rock in a horizontal circle of radius 3.6 m at a speed of 16.12 m/s. The str
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Answer:

6010.457N

Explanation:

Centripetal acceleration = a= V²/R

At a radius of 3.6m and velocity of 16.12m/s,

Acceleration is

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Force = Mass (m) * Acceleration (a)

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At breaking point

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a = V²/R = 75.1²/0.468

a = 12051.3 m/s

F = Mass(m) * Acceleration (a)

F = m * 12051.3

m = F/ 12051.3

Settings the ratio of mass equal

m = m

=> 36/72.182 = F/12051.3

F = 12051.3 * 36/72.182

F = 6010.457N

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