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Marta_Voda [28]
3 years ago
13

A thermometer has its term marked millimeter instead of degree celcuis .The lower fixed point is 30mm and upper fixed point is 1

8mm.Calculate degree celcuis when the thermometer records 45mm
Physics
1 answer:
tekilochka [14]3 years ago
8 0

Answer:

-125 degree celcuis

Explanation:

Using the formula;

θ - 0/100 - 0 = 45 - 30/18 - 30

Let us recall that the right hand side refers to the temperature in degrees centigrade while the right hand side stands for the temperatures in the scale of the thermometer. In both cases, the denominator is the fundamental interval.

So, we have;

θ/100 = 15/(-12)

-12θ = 1500

θ = 1500/(-12)

θ = -125 degree celcuis

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What is buoyancy? How is it related to the force of gravity?
boyakko [2]

Answer:

buoyancy is the ability to float on water or other liquids. this relates to the force of gravity because the stronger that force, the more likely it is to sink.

Explanation:

5 0
3 years ago
A 1.50 cm high diamond ring is placed 20.0 cm from a concave mirror with radius of curvature 30.00 cm. The magnification is ____
Rama09 [41]

Answer:

Magnification, m = -0.42

Explanation:

It is given that,

Height of diamond ring, h = 1.5 cm

Object distance, u = -20 cm

Radius of curvature of concave mirror, R = 30 cm

Focal length of mirror, f = R/2 = -15 cm (focal length is negative for concave mirror)

Using mirror's formula :

\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}, f = focal length of the mirror

\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}

\dfrac{1}{v}=\dfrac{1}{-15}+\dfrac{1}{-20}

v = -8.57 cm

The magnification of a mirror is given by,

m=\dfrac{-v}{u}

m=\dfrac{-(-8.57)}{-20}

m = -0.42

So, the magnification of the concave mirror is 0.42. Thew negative sign shows that the image is inverted.

5 0
4 years ago
A 70.0 kg70.0 kg ice hockey goalie, originally at rest, has a 0.170 kg0.170 kg hockey puck slapped at him at a velocity of 41.5
Elza [17]

Answer:

0.2012 m/s

- 41.3 m/s

Explanation:

M = mass of ice hockey goalie = 70 kg

V = initial velocity of the hockey goalie = 0 m/s

V' = final velocity of hockey goalie after collision = ?

m = mass of hockey puck = 0.170 kg

v = initial velocity of hockey puck = 41.5 m/s

v' = final velocity of hockey puck = ?

Using conservation of momentum

M V + m v = M V' + m v'

(70) (0) + (0.170) (41.5) = (70) V' + (0.170) v'

7.055 = (70) V' + (0.170) v'

V' = 0.1008 - 0.00243 v'                                       eq-1

Using conservation of kinetic energy

(0.5) M V² + (0.5) m v² =  (0.5) M V'² + (0.5) m v'²

M V² + m v² = M V'² + m v'²

(70) (0)² + (0.170) (41.5)² = (70) V'² + (0.170) v'²

292.8 = (70) V'² + (0.170) v'²

Using eq-1

292.8 = (70) (0.1008 + 0.00243 v')² + (0.170) v'²

v' = - 41.3 m/s

Using eq-1

V' = 0.1008 - 0.00243 v'

V' = 0.1008 - 0.00243 (- 41.3)

V' = 0.2012 m/s

6 0
4 years ago
As a recreational boat operator, what actions must you take when in a narrow channel?
alexandr402 [8]
One should never anchor in a narrow channel, until unless required very importantly. One should stay to the starboard side, and use a prolonged blast. The announcement must be done to alarm the nearby vessels, about your approach. The vessel should be kept at the outer limit of the starboard side. 
6 0
3 years ago
Read 2 more answers
If the fly experienced a force of 100 N when it hits how big was the force on the vehicle in this collision
iogann1982 [59]

Answer:

100N

Explanation:

because newton's third law of motion states that if body A exerts a force on the body B, then Body B will exert an equal force but opposite in direction force on body A

so if the fly experienced 100N, then the car will also experience 100N

hope you get it

please mark

8 0
3 years ago
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