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Mariana [72]
3 years ago
14

What do the electrons affected by illumination do when they are made to vibrate with greater energy?

Chemistry
1 answer:
Lera25 [3.4K]3 years ago
5 0

Answer:

These high energy electrons reemit radiation and produce color according to the frequency of the

emitted light.

OR The energized electrons reemit the light.

Explanation:

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belka [17]

Answer:

d

Explanation:

3 0
3 years ago
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What is produced by a neutralization reaction between an arrhenius acid and an arrhenius base?
stepladder [879]

Answer: Salt and Water

Explanation:

An Arrhenius acid (HCl) can best be defined as any substance that when added to water increases the concentration of H+ ions.

While an Arrhenius base (KOH) is any substance that when added to water increases the concentration of OH- ions.

When an Arrhenius acid such as HCl reacts with an Arrhenius base such as KOH, the end products will be salt and water, in a process called Neutralization Reaction.

HCl (aq) + KOH (aq)  -------> KCl (aq) + H2O (l)

4 0
3 years ago
80. Calculate AHıxn for the reaction:<br><br> CaO(s) + CO2(g) → CaCO3().
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6 0
3 years ago
A sample of propane(c3h8)has 3.84x10^24 H atoms.
deff fn [24]

Answer:

A) 14. 25 × 10²³ Carbon atoms

B) 34.72 grams

Explanation:

1 molecule of Propane has 3 atoms of Carbon and 8 atoms of Hydrogen.

The sample has 3.84 × 10²⁴ H atoms.

If 8 atoms of Hydrogrn are present in 1 molecule of propane.

3.84 × 10²⁴ H atoms are present in

\mathfrak{ \frac{3.8 }{8} \times 10 ^{24}}

<u>= 4.75 × 10²³ molecules of Propane</u>.

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

No. of Carbon atoms in 1 molecule of propane = 3

=> C atoms in 4.75× 10²³ molecules of Propane = 3 × 4.75 × 10²³

<u>= 14.25 × 10²³ </u>

<u>________________________________________</u>

<u>Gram</u><u> </u><u>Molecular</u><u> </u><u>Mass</u><u> </u><u>of</u><u> </u><u>Propane</u><u>(</u><u>C3H8</u><u>)</u>

= 3 × 12 + 8 × 1

= 36 + 8

= 44 g

1 mole of propane weighs 44g and has 6.02× 10²³ molecules of Propane.

=> 6.02 × 10²³ molecules of Propane weigh = 44 g

=> 4. 75 × 10²³ molecules of Propane weigh =

\mathsf{ \frac{44 }{6.02 \times  {10}^{23} } \times 4.75 \times  {10}^{23}  }

\mathsf{  = \frac{44 }{6.02 \times   \cancel{{10}^{23} }} \times 4.75 \times \cancel{ {10}^{23}}  }

\mathsf{  = \frac{44 }{6.02 } \times 4.75   }

<u>= 34.72 g</u>

8 0
2 years ago
Which of the following is true regarding nuclear fission and nuclear fusion?
Zarrin [17]
<h2>Nuclear Fission and Nuclear Fusion - Option C</h2>

Nuclear fission and nuclear fusion both of these processes can provide energy. Nuclear fission is the process in which heavy nucleus splits into smaller parts. When they split into smaller particles then it releases energy.

On the other hand, nuclear fusion is the process in which small particles fuse together to form a heavy nucleus. With the formation of heavy nucleus, it also provides energy.

Therefore, both these processes release or provide energy.

3 0
3 years ago
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