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2 years ago

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Define the term 'structural isomerism'.

1 answer:

emmasim [6.3K]2 years ago

5 0

Answer:

In chemistry, a structural isomer (or constitutional isomer in the IUPAC nomenclature) of a compound is another compound whose molecule has the same number of atoms of each element, but with logically distinct bonds between them. The term metamer was formerly used for the same concept.

Explanation:

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What is the connection of ascorbic acid when one tablet is dissolved in 200cm cubed of water ?

BartSMP [9]

Answer:

Option-D: 2.3 × 10⁻³ mol/dm³

Explanation:

Calculate moles of ascorbic acid,

Moles = Mass / M.Mass

Moles = 0.080 g / 176 g/mol

Moles = 0.00045 mole

Also,

Molarity = Moles / Vol. in dm³

Molarity = 0.00045 mol / 0.20 dm³

Molarity = 0.00227 mol.dm⁻¹ or 2.3 × 10⁻³ mol/dm³

5 0

2 years ago

A solution is made by adding 29.1 mL of concentrated perchloric acid ( 70.5 wt% , density 1.67 g/mL ) to some water in a volumet

Lera25 [3.4K]

Answer:

The concentration of the solution is 1.364 molar.

Explanation:

Volume of perchloric acid = 29.1 mL

Mass of the solution = m

Density of the solution = 1.67 g/mL

$m=1.67 g/mL\times 29.1 mL=48.597 g$

Percentage of perchloric acid in 48.597 solution :70.5 %

Mass of perchloric acid in 48.597 solution :

= $\frac{70.5}{100}\times 48.597 = 34.261 g$

Moles of perchloric acid = $\frac{34.261 g}{100.46 g/mol}=0.3410 mol$

In 29.1 mL of solution water is added and volume was changed to 250 mL.

So, volume of the final solution = 250 mL = 0.250 L (1 mL = 0.001 L)

$Molarity=\frac{Moles}{Volume (L)}$

$=\frac{0.3410 mol}{0.250 L}=1.364 M$

The concentration of the solution is 1.364 molar.

6 0

3 years ago

For each pair, which has higher potential energy?

Allushta [10]

Answer:

Maybe A)

Explanation:

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7 0

3 years ago

how much current would be measured in a circuit if the light bulb has a resistance of 6 ohms and a voltage of 36 volts

Stels [109]

Answer:

The right response is "6 A". A further explanation is given below.

Explanation:

The given values are:

Resistance,

R = 6 ohms

Voltage,

V = 36 volts

As we know,

⇒ $V=IR$

then,

⇒ $I=\frac{V}{R}$

On substituting the values, we get

⇒ $=\frac{36}{6}$

⇒ $=6 \ A$

8 0

2 years ago

How do I do this? It's in Chemistry, and it has to do with Single Replacement

Setler [38]

Is there any more to the picture?

4 0

3 years ago