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3 years ago

Which one is it ASAP

Chemistry

2 answers:

Gelneren [198K]3 years ago

6 0

4 is D. 5 is C. 6 is D i guess. 7 is D.

crimeas [40]3 years ago

4 0

Question 4 answer: Gravity only pulls large objects together.

Question 5 answer: Friction

Question 6 answer: Unbalanced Force

Question 7 answer: Reaction Force.
Hope this helps!

Aye sir!

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2AgNO3 + BaCl2 → 2AgCl + Ba(NO3)2

miv72 [106K]

<h3>Answer:</h3>

4 g AgCl

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Stoichiometry</u>

Reading a Periodic Table
Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN] 2AgNO₃ + BaCl₂ → 2AgCl + Ba(NO₃)₂

[Given] 5.0 g AgNO₃

<u>Step 2: Identify Conversions</u>

[Reaction - Stoich] 2AgNO₃ → 2AgCl

Molar Mass of Ag - 107.87 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of AgNO₃ - 107.87 + 14.01 + 3(16.00) = 169.88 g/mol

Molar Mass of AgCl - 107.87 + 35.45 = 143.32 g/mol

<u>Step 3: Stoichiometry</u>

Set up: $\displaystyle 5.0 \ g \ AgNO_3(\frac{1 \ mol \ AgNO_3}{169.88 \ g \ AgNO_3})(\frac{2 \ mol \ AgCl}{2 \ mol \ AgNO_3})(\frac{143.22 \ g \ AgCl}{1 \ mol \ AgCl})$
Multiply/Divide: $\displaystyle 4.21533 \ g \ AgCl$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig.</em>

4.21533 g AgCl ≈ 4 g AgCl

3 0

3 years ago

In an area in which electricity costs 8 cents/kilowatt-hour, a 5 kW clothes dryer runs for 90 minutes to dry a load of laundry.

Orlov [11]

90 minutes is 1.5 hours.

5 kW * 1.5 hours = 7.5 kWh

8c/kWh * 7.5 kWh = 60 cents

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3 years ago

What factor would affect the pH of a waterway?

just olya [345]

Acid Rain. Hope i helped you!

8 0

4 years ago

How many moles of Al(CN)3 are in 183 g of the compound?

Lyrx [107]

You need to calculate the molar mass for Al(CN)3 using the atomic weights for Al, C, and N given on the periodic table.

1 Al (26.98) + 3 C (3 x 12.01) + 3 N (3 x 14.01) = 105.04 g Al(CN)3 / mole

183 g Al(CN)3 x (1 mole Al(CN)3 / 105.04 g Al(CN)3) = 1.74 moles Al(CN)3

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4 years ago

Need help ASAP plzzzzzz

oee [108]

Answer:

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3 years ago