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3 years ago

Which term names enzymes in the body that speed up chemical reactions? A. catalysts B. cells C. concentrations D. chloroplasts

Chemistry

2 answers:

vazorg [7]3 years ago

8 0

Carbonic anhydrase speeds up the transfer of carbon dioxide from cells to the blood.

Hope this work cuz

lutik1710 [3]3 years ago

7 0

Catalyst speeds up the chemical reactions. Catalyst is the compound that adds to the chemical reaction so that it happen more quickly. Catalyst without being consumed in the reaction accelerates the reaction. It lowers down the activation energy of the transition state and thus accelerates the reaction.

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what is the predicted order of fist ionization energies from highest to lowest for beryllium, calcium, magnesium, and stronium?

MrRa [10]

Lowest to highest:
Ca
Mg
Be
S

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3 years ago

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True or False:

bezimeni [28]

The answer is B, false

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3 years ago

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Calculate the radius of tantalum (Ta) atom, given that Ta has a BCC crystal structure, a density of 16.6 g/cm, and an atomic wei

Ivahew [28]

Answer:

The radius of tantalum (Ta) atom is $R = 1.43 \times 10^{-8} \:cm = 0.143 \:nm$

Explanation:

From the Body-centered cubic (BBC) crystal structure we know that a unit cell length a and atomic radius R are related through

$a=\frac{4R}{\sqrt{3} }$

So the volume of the unit cell $V_{c}$ is

$V_{c}= a^3=(\frac{4R}{\sqrt{3} } )^3=\frac{64\sqrt{3}R^3}{9}$

We can compute the theoretical density ρ through the following relationship

$\rho=\frac{nA}{V_{c}N_{a}}$

where

n = number of atoms associated with each unit cell

A = atomic weight

$V_{c}$ = volume of the unit cell

$N_{a}$ = Avogadro’s number ( $6.023 \times 10^{23}$ atoms/mol)

From the information given:

A = 180.9 g/mol

ρ = 16.6 g/cm^3

Since the crystal structure is BCC, n, the number of atoms per unit cell, is 2.

We can use the theoretical density ρ to find the radio R as follows:

$\rho=\frac{nA}{V_{c}N_{a}}\\\rho=\frac{nA}{(\frac{64\sqrt{3}R^3}{9})N_{a}}$

Solving for R

$\rho=\frac{nA}{(\frac{64\sqrt{3}R^3}{9})N_{a}}\\\frac{64\sqrt{3}R^3}{9}=\frac{nA}{\rho N_{a}}\\R^3=\frac{nA}{\rho N_{a}}\cdot \frac{1}{\frac{64\sqrt{3}}{9}} \\R=\sqrt[3]{\frac{nA}{\rho N_{a}}\cdot \frac{1}{\frac{64\sqrt{3}}{9}}}$

Substitution for the various parameters into above equation yields

$R=\sqrt[3]{\frac{2\cdot 180.9}{16.6\cdot 6.023 \times 10^{23}}\cdot \frac{1}{\frac{64\sqrt{3}}{9}}}\\R = 1.43 \times 10^{-8} \:cm = 0.143 \:nm$

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3 years ago

Predict whether the following double-replacement reaction will produce a precipitate: MgCl2 + Li2CO3 MgCO3 + 2 LiCl.

nata0808 [166]

I think the correct answer from the choices listed above is the second option. This is a double displacement reaction. Both of the reactants are soluble, but when they are combined for a reaction, magnesium carbonate will form a precipitate. Hope this answers the question.

5 0

3 years ago

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If aqueous solutions of sodium chloride and mercury(I) nitrate are mixed, which insoluble precipitate is formed?

NeX [460]

Answer:

Hg2^2+(aq) + 2Cl^-(aq) —> Hg2Cl2(s)

Explanation:

The balanced equation for the reaction is given below:

2NaCl(aq) + Hg2(NO3)2(aq) —> 2NaNO3(aq) + Hg2Cl2(s)

Considering the states of each compound in the reaction, we can see that Hg2Cl2 is in solid form meaning it will precipitate out of the solution

In solution the following occurs:

NaCl —> Na+(aq) + Cl-(aq)

Hg2(NO3)2 —> Hg2^2+(aq) + 2NO3^-(aq)

Combining the two equation together, a balanced double displacement reaction occurs as shown below:

2Na+(aq) + 2Cl-(aq) + Hg2^2+(aq) + 2NO3^-(aq) —> 2Na+2NO3^-(aq) + Hg2^2+2Cl-(s)

From the above we can thus right the insoluble precipitate as

Hg2^2+(aq) + 2Cl^-(aq) —> Hg2Cl2(s)

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3 years ago