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4 years ago

Why don't you hear a sound when you move your hand back and fourth through the air

2 answers:

5 0

You can't move your hand fast enough, the lowest frequency sound is about 20 cycles per second, if you could move your hand that fast, you might hear sound.

inessss [21]4 years ago

3 0

Your hand is not capable of moving fast enough for sound to come out of it.

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Place thermometers near the edge of the table for easy retrieval.

Maurinko [17]

This is a true and false question correct or did you accidentally put two truths ??

7 0

3 years ago

WILL MARK BRAINLIEST!

viva [34]

Answer:

True

Explanation:

Newton's first law of motion states that an object at rest will stay at rest unless acted upon by an outside force.

5 0

3 years ago

Read 2 more answers

A 75 g bullet is fired from a rifle having a barrel 0.650 m long. Assuming the origin is placed where the bullet begins to move,

kolbaska11 [484]

Answer:

7557.875 J

Explanation:

Assumimg we need to find work done by the bullet on the gas

The work is found by integrating force over distance

W= $W=\int_{x_i}^{x_f}F.ds$

For the force in this problem we have

$W=\int_{0}^{0.65}14000 + 10000x - 21000x^2.ds$

= $[14000x+10000x^2-21000x^3]_{0}^{0.65}$

=7557.875 J

8 0

3 years ago

A small object with a 5.0-mC charge is accelerating horizontally on a friction-free surface at 0.0050 m/s2 due only to an electr

kolbaska11 [484]

Answer:

$0.002 N/C$

Explanation:

Parameters given:

Charge of object, q = 5 mC = $5 * 10^{-3} C$

Acceleration of object, a = $0.005 m/s^2$

Mass of object, m = 2.0 g

The Electric field exerts a particular force on the object, causing it to accelerate (Electrostatic force).

We know that Electrostatic force, F, is given in terms of Electric field, E, as:

F = qE

This means that the object exerts a force of -qE on the Electric force (Action with equal and opposite reaction).

The object also has a force, F, due to its acceleration a. This force is the product of its mass and acceleration. Mathematically:

F = ma

Equating the two forces of the object, we get:

-qE = ma

=> $E = \frac{-ma}{q}$

Solving for E, we have:

$E = \frac{-2 * 10^{-3} * 0.005}{5 * 10^{-3}} \\\\\\E = -0.002 N/C$

The magnitude will be:

$|E| = |-0.002| N/C = 0.002 N/C$

The electric field has a magnitude of 0.002 N/C.

4 0

3 years ago

Under what condition will the enthalpy change of a process equal the amount of heat transferred into or out of the system?

olga55 [171]

Answer:

At constant pressure

Explanation:

Enthalpy of a system may be defined as the system's internal energy in addition to the product of the volume and pressure of the system.

It can be regarded as the system's capacity of heat transfer and to do non- mechanical work.

The enthalpy of the system at constant pressure gives the amount of heat or energy that is either absorbed by the system or released by the system.

3 0

3 years ago