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lidiya [134]
3 years ago
9

In a circuit, electrons flow from _____ terminal to the ____ terminal.​

Physics
1 answer:
malfutka [58]3 years ago
3 0

Answer:

phyiscal, work out

Explanation:

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What is the heat extracted from the cold reservoir for the refrigerator?
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What is the heat extracted from the cold reservoir for the refrigerator shown in(Figure 1) ? Assume that W1 = -123J and W2 = 88J . 

<span>Qc= _________ </span>

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K=105J
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3 years ago
A block with m = 300 grams oscillates at the end of a linear spring with k = 6.5 N/m. (assume this is a top-down view and the bl
inna [77]

Answer:

a) T=1.35s

b) amplitude = 0.0923m

Explanation:

m=300 gr

k=6.5 N/m

first we need to get the angular frequency of the motion

so we have that

ω = √(k/m)

in this case motion is a simple harmonic so the period is defined by:

T= 2π / ω

T= 2π / √(k/m)

replacing the variables...

T= 2π / √(6.5/0.3)

T=1.35s   (period of the block's motion)

and...

α max = | ω²r max |

2 = (2π/1.35)² * r max

r max= 0.0923m

6 0
3 years ago
Science help answer all
wlad13 [49]
Idk but i hope you figure it out :)
4 0
3 years ago
A car accelerates from 20 m\s to 30 m\s in 2 seconds. What is the average acceleration of the car?
Morgarella [4.7K]

Answer: Acceleration =5m/s^2

Explanation:

3 0
2 years ago
Two 2.0cm×2.0cm metal electrodes are spaced 1.0 mm apart and connected by wires to the terminals of a 9.0 v battery. What is the
Fantom [35]

Answer:

The charge on each electrode is

q=0.354 x10^{-12}

Explanation:

The charge to find the equation is development

V=9v

d=1.0 mm\\A=2cm*2cm=0.02m*0.02m\\A=4x10^{-4} \\E_{o} =8.85x10^{-12} (\frac{C^{2} }{N*m^{2} } )

q=C*V

C=\frac{E_{o}*A }{d} \\C=\frac{8.85x10^{-12} *4x10^{-4}  }{0.01}=0.354  \\

q=0.354*9v\\q=3.186x10^{-12} C

3 0
3 years ago
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