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katen-ka-za [31]
3 years ago
14

Y=-3x+2 I need help plssssssss

Mathematics
1 answer:
kirill [66]3 years ago
8 0
Graphing or solving for variable? I can solve for either. Of your looking for a graph just comment but I can help you when looking for a variable. So I don’t know if your solving for x or y but I will assume your solving for x. So,
1. Flip the equation; -3x+ 2 = y
2. Add -2 to both sides
3. Divide both sides by -3
Your answer: x= -1/3y + 2/3.
Feedback is appreciated along with brainliest :-)
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Using appropriate properties find: 2/3 × 3/4 + 3/7 × 3/4​
Viktor [21]

Answer:

\frac{23}{28}

Step-by-step explanation:

\frac{2}{3}  \times  \frac{3}{4}  +  \frac{3}{7}  \times  \frac{3}{4}

=  >  \frac{3}{4} ( \frac{2}{3}  +  \frac{3}{7} )

=  >  \frac{3}{4}  \times  \frac{23}{21}

Reducing 3 from numerator and denominator,

=  >  \frac{23}{4 \times 7}  =  \frac{23}{28}

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2 years ago
On a coordinate plane, a curved line with a minimum value of (negative 2.5, negative 12) and a maximum value of (0, negative 3)
goldfiish [28.3K]

Answer:

f(x) > 0 over the interval (-\infty,-4)

Step-by-step explanation:

If  f(x)  is a continuous function,  and that all the critical points of behavior change are described by the given information, then we can say that the function crossed the x axis to reach a minimum value of -12 at the point x=-2.5, then as x increases it ascends to a maximum value of -3 for x = 0 (which is also its y-axis crossing) and therefore probably a local maximum.

Then the function was above the x axis (larger than zero) from - \infty, until it crossed the x axis (becoming then negative) at the point x = -4. So the function was positive (larger than zero) in such interval.

There is no such type of unique assertion regarding the positive or negative value of the function when one extends the interval from - \infty to -3, since between the  values -4 and -3 the function adopts negative values.

6 0
3 years ago
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Step-by-step explanation:

f(x) = 1

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Answer:

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Step-by-step explanation:

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