2 years ago

This type of formula indicates the kind, number, arrangement, and bonds but not the unshared pairs of the atoms in a molecule.

Chemistry

1 answer:

valentina_108 [34]2 years ago

7 0

Electronic configuration

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Zarrin [17]

Answer:

Explanation:

Each coil increases it by a multiple of 100.

=> 50 | 3 | 15,000

=> 100 | 3 | 30,000

=> 150 | 3 | 45,000

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2 years ago

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254950m to millimeter

Arte-miy333 [17]

254950000 millimeters

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2 years ago

Find the density.... Mass is 138g and Volume is 100 mL

solniwko [45]

Answer:

1380 kilogram/cubic meter

$p=\frac{m}{v}$

$=\frac{138g}{100mL}$

$=1.38$

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3 years ago

A 250 mL sample of gas is collected over water at 35°C and at a total pressure of 735 mm Hg. If the vapor pressure of water at 3

ELEN [110]

Answer:

The volume of the gas sample at standard pressure is 819.5ml

Explanation:

Solution Given:

let volume be V and temperature be T and pressure be P.

$V_1=250ml$

$V_2=?$

$P_{total}=735 mmhg$

1 torr= 1 mmhg

42.2 torr=42.2 mmhg

so,

$P_{water}=42.2mmhg$

$T_1=35°C=35+273=308 K$

Now

firstly we need to find the pressure due to gas along by subtracting the vapor pressure of water.

$P_{gas}=P_{total}-P_{water}$

=735-42.2=692.8 mmhg

Now

By using combined gas law equation:

$\frac{P_1*V_1}{T_1} =\frac{P_2*V_2}{T_2}$

$V_2=\frac{P_1*}{P_2}*\frac{T_2}{T_1} *V_1$

$V_2=\frac{P_gas}{P_2}*\frac{T_2}{T_1} *V_1$

Here $P_2 \:and\: T_2$ are standard pressure and temperature respectively.

we have

$P_2=750mmhg \:and\: T_2=273K$

Substituting value, we get

$V_2=\frac{692.8}{750}*\frac{273}{308} *250$

$V_2= 819.51 ml$

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1 year ago

Write your name on a piece of paper with a water soluble marker and place the slime on top of it and remove very quickly before

creativ13 [48]

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2 years ago