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Maslowich
2 years ago
14

You have an object with a mass of 14 g and a volume of 20 mL. Calculate the density and identify which material you have from th

e list.
Chemistry
1 answer:
arsen [322]2 years ago
8 0

Answer:

0.7 g/ml. Whichever material matches that closest is the right one.

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What form of matter is made from only one type of atom? compound molecule material element
Lelechka [254]
<span>Elements are matter made of one kind of atom.</span>
6 0
3 years ago
Read 2 more answers
A scuba diver that ascends to the surface too quickly can experience decompression sickness, which occurs when nitrogen that dis
Butoxors [25]

Answer:

The factor that will change the volume of the diver's lungs upon reaching the surface is 4

Explanation:

Given data:

Pressure increases 1 atm = 101.325 kPa

34 ft = 10.3632 m

Depth of 102 ft = 31.0896 m

Question: What factor will the volume of the diver's lungs change upon arrival at the surface, V₂/V₁ = ?

The pressure at 31.0896 m:

P_{1} =101.325+(\frac{31.0896}{10.3632} *101.325)=405.3kPa

The factor will the volume of the diver's lungs change upon arrival at the surface:

\frac{V_{2}}{V_{1} } =\frac{P_{1}}{P_{2}} =\frac{405.3}{101.325} =4

5 0
3 years ago
How many joules of heat are needed to change 50.0 grams of ice at 0 C to boil at 120.0 C? Show work
Tcecarenko [31]
This can be done in the following way;
1 determining the heat required to convert 0° C ice to 0°C water
 Heat of fusion of water = 334  J/g
Therefore; Heat = 50 g × 334 J/g =  16700 J
2. Determining the heat required to raise the temperature of water from 0° C to 100°C.
Specific heat of water is 4.18 J/g°C
Change in temperature is 100°C
Therefore; Heat = 50 g × 4.18 J/g°C × 100 = 20900 J
3. Determining the heat required to convert 100 ° C water to 100°C vapor
Heat of vaporization of water = 2257 J/g
Heat = Mass of water × heat of vaporization
Heat = 50 g × 2257 = 112850 J
4. Determining the heat required to go from 100° C to 120° vapor
specific heat of vapor = 2.09 J/g°C
Heat = mass × Specific heat of vapor × change in temperature
        = 50 g × 2.09 ×(120-100) = 2090 J

Therefore the total heat required is 
 = 16700 J + 20900 J + 112850 J + 2090 J =  152540 J or 152.54 kJ

6 0
3 years ago
How many amperes would be needed to produce 60.0 grams of magnesium during the electrolysis of molten mgcl 2 in 2.00 hours?
Shalnov [3]

Answer:

\boxed{\text{66.2 A}}

Explanation:

1. Write the equation for the reaction.

M_r:                 24.30

          MgCl₂ ⟶ Mg + Cl₂

m/g:                   60.0

2. Calculate the moles of Mg

Moles of Mg = 60.0 g Mg × (1 mol Mg/ 24.30 g Mg) = 2.469 mol Mg

3. Calculate the moles of electrons

Moles of electrons = 2.469 mol Mg × (2 mol electrons/1 mol Mg)

= 4.938 mol electrons

4. Calculate the number of coulombs

Q = 4.938 mol electrons × (96 485 C/1 mol electrons) = 476 500 C

5. Calculate the current required

Q  = It

I = Q/t

t = 2.00 h × (60 min/1h) × (60 s/1 min) = 7200 s

I = 476 500 C/7600 s= 66.2 C/s = 66.2 A

You need a current of \boxed{\textbf{66.2 A}}.

8 0
4 years ago
HELPPP MEEEEEEEEEEEEEEEE​
KonstantinChe [14]

This is your answer white blood cells (WBC)

4 0
3 years ago
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