What are the two components of a solution
1 answer:
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Answer:
A) he equilibrium concentration of PH3 = 0.0432M
B) he equilibrium concentration of BCl3 = 0.0432M
C) what is the minimum mass of PH3BCl3(s) that must be added to the flask to achieve equilibrium = 1.69g
Explanation:
The detailed steps and appropriate calculation is as shown in the attached file.
Moles of solute for both a and b are the same = 1 mol
<h3>Further explanation</h3>Given
a 500 cm³ of solution, of concentration 2 mol/dm³
b 2 litres of solution, of concentration 0.5 mol/dm³
Required
moles of solute
Solution
Molarity shows the number of moles of solute in every 1 liter of solution or mmol in each ml of solution
Can be formulated :
a.
V = 500 cm³ = 0.5 L
M = 2 mol/L
n=moles = M x V
n = 2 mol/L x 0.5 L
n = 1 mol
b.
V = 2 L
M = 0.5 mol/L
n=moles = M x V
n = 0.5 mol/L x 2 L
n = 1 mol