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Nastasia [14]
2 years ago
7

A sample of gas with a volume of 30.0 ml at 25.0c is heated to 50.0c what is the new volume of the gas

Chemistry
1 answer:
garik1379 [7]2 years ago
7 0

Answer:

The new volume is 60ml

Explanation

using the equation p1v1/n1t1=p2v2/n2t2 we would divied 30 by 25 the multiply by 50 to get 60

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How many grams of calcium chloride will be produced when 29.0 g of calcium carbonate is combined with 15.0 g of hydrochloric aci
horsena [70]

Answer:

22.7 g of CaCl₂ are produced in the reaction

Explanation:

This is the reaction:

CaCO₃ +  2HCl  →  CaCl₂  + CO₂  +  H₂O

Now, let's determine the limiting reactant.

Let's divide the mass between the molar mass, to find out moles of each reactant.

29 g / 100.08 g/m = 0.289 of carbonate

15 g / 36.45 g/m = 0.411 of acid

1 mol of carbonate must react with 2 moles of acid

0.289 moles of carbonate will react with the double of moles (0.578)

I only have 0.411 of HCl, so the acid is the limiting reactant.

Ratio is 2:1, so I will produce the half of moles, of salt.

0.411 / 2 = 0.205 moles of CaCl₂

Mol . molar mass = mass → 0.205 m . 110.98 g/m = 22.7 g

5 0
3 years ago
How many bromine atoms are present in 39.4 g of CH2Br2
strojnjashka [21]
37.8 g CH2Br2 X (1 mol CH2Br2 / 173.83 g) = 4.60X10^-3 mol CH2Br2 

<span>4.60X10^-3 mol CH2Br2 X (2 mol Br / 1 mol CH2Br2) X 6.02X10^23 atoms/mol = 5.54X10^21 bromine atoms</span>
7 0
3 years ago
Which organism is the carnivore in this food web?
mihalych1998 [28]
Among the choices, the only one that can be considered a carnivore is C. Adelie penguin. Adelie penguins are found in the Arctic, and feed on aquatic creatures such as krill, fish, and squid. Krill is a type of crustacean that feeds on phytoplankton, which is at the bottom of the food chain.
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3 years ago
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3 years ago
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What is the concentration of a solution in which 10.0 g of AgNO, is dissolved in 450 mL of solution?
Rufina [12.5K]

Answer:

M=0.15

Explanation:

138 g AgNO -> 1 mol AgNO

10 g AgNO   -> x

x= (10 g AgNO * 1 mol AgNO)/138 g        x=0.07 mol AgNO

450 mL=0.45 L

M= mol solute/L solution

M= 0.07 mol AgNO/0.45L

M=0.15

4 0
3 years ago
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