Answer:
Heat required = 13,325 calories or 55.75 KJ.
Explanation:
To convert a water to steam at 100 degree celsius to vapor, we have to give latent heat of vaporization to water
Which equals ,
Q = mL,
Where, m is the mass of water present
L = specific latent heat of vaporization
Here , m= 25 gram
L equals to 533 calories (or 2230 Joules)
So, Q = 25×533 = 13,325 Calories
Or , Q = 55,750 Joules = 55.75 KJ
so, Heat required = 13,325 calories or 55.75 KJ.
Answer:
Enantiomers/ Isomers/ Stereoisomers/ Meso compounds/ Constitutional isomers/ Diastereomers.
Explanation:
Isomers are molecules that have the same chemical formula but have different conformation, or in its connections, or the orientation in space. Isomers have different chemical and physical properties (second blank).
The isomers that only differ by the orientation of their atoms in space are called stereoisomers (third blank).
The stereoisomers that have a chiral carbon and do not mirror images of each are called enantiomers (first blank). They can deviate the polarized light.
When a compound has two or more chiral carbons but they compensate for the deviation of the light, and the compound is optically inactive, it's called a meso compound (fourth blank).
When the isomers differ in the way the atoms are connected it's called a constitutional isomer (fifth blank).
When the molecule has more than one chiral carbon, it will have pairs of enantiomers. The isomers that aren't of the same pair are nonsuperimposable mirror images of each other and are called diastereomers (last blank).
Answer:
P.E for the 4kg bowling ball held 2.5 meters above head is 100j, while the other is 60j so the 4kg ball has more potential energy
<h3>Balanced equation :
2C₂H₆ (g) + 7O₂ (g) ⟶ 4CO₂ (g) + 6H₂O (ℓ)</h3><h3>Further explanation</h3>
Alkanes are saturated hydrocarbons that have single bonds in chains
General formula for alkanes :

Hydrocarbon combustion reactions (specifically alkanes)

So that the burning of ethane with air (oxygen):

2C₂H₆ (g) + 7O₂ (g) ⟶ 4CO₂ (g) + 6H₂O (ℓ)
or we can use mathematical equations to solve equilibrium chemical equations by giving the coefficients for each compound involved in the reaction
C₂H₆ (g) + aO₂ (g) ⟶ bCO₂ (g) + cH₂O (ℓ)
C : left 2, right b ⇒ b=2
H: left 6, right 2c⇒ 2c=6⇒ c= 3
O : left 2a, right 2b+c⇒ 2a=2b+c⇒2a=2.2+3⇒2a=7⇒a=7/2