The formula of the hydrate = CuSO₄• 3H₂O
<h3>Further explanation</h3>
Given
4.175 grams sample CuSO₄• xH₂O
3.120 grams anhydrous compound CuSO₄
Required
The formula
Solution
mass of H₂O driven off :
= 4.175 - 3.12
= 1.055 g
MW CuSO₄ = 159.5 g/mol
MW H₂O = 18 g/mol
mol ratio of CuSO₄ : H₂O :
= 3.12/159.5 : 1.055/18
= 0.01956 : 0.05861
= 1 : 3
An acid is a compound which will give H+ ions or H3O^+ ions
the reaction will be
![[Mn(H_{2}O )_{6} ^{+3} +H_{2}O --> [MnOH(H_{2}O)_{5}]^{+2} + H_{3}O^{+}](https://tex.z-dn.net/?f=%5BMn%28H_%7B2%7DO%20%29_%7B6%7D%20%5E%7B%2B3%7D%20%2BH_%7B2%7DO%20--%3E%20%5BMnOH%28H_%7B2%7DO%29_%7B5%7D%5D%5E%7B%2B2%7D%20%2B%20H_%7B3%7DO%5E%7B%2B%7D)
Thus as there is evolution of H_{3}O^{+} the Mn+3 is an acid
You must add 45 mL of the 80 % alcohol to the 30 % alcohol to get a 35 % solution.
You can use a modified dilution formula to calculate the volume of 80 % alcohol
V1×C1 + V2×C2 = V3×C3
Let the volume of 80 % mixture 1 = <em>x</em> mL. Then the volume of the final 35 % mixture 3 = (405 + <em>x</em> ) mL
(<em>x</em> mL×80 % alc) + (405 mL×30 % alc) = (405 + <em>x</em>)mL × 35 % alc
80x + 12 150 = 14 175 + 35 x
45x = 2025
x = 2025/45 = 45
Answer:
oxygen
Explanation:
The given isotope has 8 protons and 8 electrons, so the atomic number of the given isotope is 8, which is the atomic number of oxygen.
Following steps are involved in the reaction
Step 1: <span>Cl2(g)⇌2Cl(g)
Step 2: </span><span>Cl(g)+CHCl3(g)→HCl(g)+CCl3(g)
Step 3: </span><span>Cl(g)+CCl3(g)→CCl4(g)
......................................................................................................
Overall reaction : </span>Cl2(g) + CHCl3(g) → HCl(g) + CCl4(g)
Note: Overall reaction is obtained by adding step 1-3 and canceling common terms that are present on reactant and product sides.
