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ololo11 [35]
3 years ago
14

Would you recommend your friend build a digester for their farm? Why or why not?

Chemistry
2 answers:
Natasha_Volkova [10]3 years ago
5 0

╔═.✵.══════════╗

      A  N  S  W  E  R

╚══════════.✵.═╝

☆ ☆ ☆

Yes :

If my friend would like to conserve heat or conduct electricity for houses, then yes!

     

<em>Hope this helped, love! </em>☆☆ ☆

dedylja [7]3 years ago
3 0
Yes! Because the digester will help with heating and keeps things warm. Along with conducting electricity for appliances
You might be interested in
A 0.216 g sample of carbon dioxide, CO2, has a volume of 507 mL and a pressure of 470 mmHg. What is the temperature of the gas i
Gala2k [10]

Answer:

The temperature of the gas is 876.69 Kelvin

Explanation:

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P*V = n*R*T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

In this case:

  • P= 470 mmHg
  • V= 570 mL= 0.570 L
  • n= 0.216 g= 0.0049 moles (being the molar mass of carbon dioxide is 44 g/mole)
  • R= 62.36367 \frac{mmHg*L}{mol*K}
  • T=?

Replacing:

470 mmHg*0.570 L= 0.0049 moles* 62.36367 \frac{mmHg*L}{mol*K} *T

Solving:

T=\frac{470 mmHg*0.570 L}{0.0049 moles* 62.36367\frac{mmHg*L}{mol*K} }

T= 876.69 K

<em><u>The temperature of the gas is 876.69 Kelvin</u></em>

6 0
3 years ago
A 13.5g sample of gold is heated, then placed in a calorimeter containing 60g of water. The temperature of water increases from
sweet-ann [11.9K]

Answer:

T_i~=163.1 ºC

Explanation:

We have to start with the variables of the problem:

Mass of water = 60 g

Mass of gold = 13.5 g

Initial temperature of water= 19 ºC

Final temperature of water= 20 ºC

<u>Initial temperature of gold= Unknow</u>

Final temperature of gold= 20 ºC

Specific heat of gold = 0.13J/gºC

Specific heat of water = 4.186 J/g°C

Now if we remember the <u>heat equation</u>:

Q_H_2_O=m_H_2_O*Cp_H_2_O*deltaT

Q_A_u=m_A_u*Cp_A_u*deltaT

We can relate these equations if we take into account that <u>all heat of gold is transfer to the water</u>, so:

m_H_2_O*Cp_H_2_O*deltaT=~-~m_A_u*Cp_A_u*deltaT

Now we can <u>put the values into the equation</u>:

60~g*4.186~J/g{\circ}C*(20-19)~{\circ}C=-(13.5~g*0.13~J/g{\circ}C*(20-T_i)~{\circ}C)

Now we can <u>solve for the initial temperature of gold</u>, so:

T_i~=(\frac{60~g*4.186~J/g{\circ}C*(20-19)~{\circ}C}{13.5~g*0.13~J/g{\circ}C})+20

T_i~=163.1 ºC

I hope it helps!

5 0
3 years ago
A volume of 90.0 mL of aqueous potassium hydroxide (KOH) was titrated against a standard solution of sulfuric acid (H2SO4). What
Gemiola [76]

Answer:

The answer to your question:  0.7 M

Explanation:

Data

V of KOH = 90 ml

[KOH] = ?

V H2SO4 = 21.2 ml

[H2SO4] = 1.5 M

                       2KOH(aq)  +  H₂SO₄(aq)   →   K₂SO₄(aq)  +  2H₂O(l)

Molarity = moles / volume

moles of H₂SO₄ = (1.5) (21.2)

                           = 31.8

                    2 moles of KOH --------------  1 mol of H₂SO₄

                   x                           --------------  31.8 mol of H₂SO₄

                    x = (31.8)(2) / 1

                    x = 63.8 moles of KOH

Molarity = 63.8 / 90

             = 0.7 M

7 0
3 years ago
Give an example of a specialized cell.
Gre4nikov [31]

Answer:

Muscle cell

Explanation:

An example of a specialized cell would be a muscle cell, which allows muscles to contract. A specialized cell has a specific function.

4 0
2 years ago
Read 2 more answers
You have a pound of feathers and a pound of lead:
mafiozo [28]
Feathers have more density and less have more mass, feather is super light and a POUND of led isnt
6 0
3 years ago
Read 2 more answers
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