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denpristay [2]
3 years ago
10

The measurable properties of a substance, such as vapor pressure and surface tension, occur due to the strength of

Chemistry
2 answers:
SpyIntel [72]3 years ago
8 0

Properties of a substance such as vapor pressure and surface tension depend on electrical forces between particles, as given by Coulomb's law.

The vapor pressure refers to how easily a liquid converts to gas while surface tension is the force that makes a liquid surface act as a stretched elastic skin.

Both vapor pressure and surface tension has a lot to do with the degree of polarity in a molecule. Usually, polar molecules have a low vapor pressure and high surface tension due to a high electrical forces between particles, as given by Coulomb's law.

Learn more: brainly.com/question/13440572

Anarel [89]3 years ago
4 0

Answer:

electrical forces between particles, as given by coulombs law.

Explanation:

You might be interested in
1.00l of octane (M=114.23 g/mol, d=0.703 g/cm3) undergoes a combustion reaction with 5.0 L of oxygen at 25 celcius and 1.0 atm p
Natalka [10]

Answer:

               2.873 g of CO₂

Explanation:

This problem will be solved in two steps.

Step 1: Calculating mass of Octane:

Data Given:

                  Volume = 1 L = 1000 cm³

                  Density  =  0.703 g/cm³

                  Mass  =  ??

Formula Used:

                       Density = Mass ÷ Volume

Solving for Mass,

                       Mass  =  Density × Volume

                       Mass  =  0.703 g/cm³ × 1000 cm³

Putting Values,

                       Mass  =  703 g

Step 2: Calculating Mass of Oxygen:

Data:

                  Volume =  V  = 5.0 L

                  Temperature = T = 25 °C = 298.15 K

                  Pressure = P = 1.0 atm

                  Moles = n = ?

Assuming that the gas is acting as Ideal gas so, we will use Ideal gas equation i.e.

                 P V = n R T

Solving for n,

                  n = P V / RT

Putting values,

                  n = 1.0 atm × 5.0 L / 0.0821 atm.L.mol⁻¹.K⁻¹ × 298.15 K

                  n = 0.204 moles

As,

            Moles = Mass / M.Mass

So,

            Mass = Moles × M.Mass

            Mass = 0.204 mol × 16 g/mol       ∴ M.Mass of O₂ = 16g.mol⁻¹

            Mass = 3.26 g

Step 3: Calculating mass of CO₂:

The balance chemical equation is follow,

                            2 C₈H₁₈ + 25 O2 = 16 CO₂ + 18 H₂O

According to equation

        228.45 g (2 mol) of C₈H₁₈  reacts with = 799.97 g (16 mol) of O₂

So,

                       703 g of C₈H₁₈ will react with = X g of O₂

Solving for X,

                  X  =  703 g × 799.97 g ÷ 228.45

                  X  =  2461 g of O₂

While, we are only provided with 3.26 g of O₂. This means O₂ is the limiting reactant and will control the yield of the final product. Therefore,

According to balance equation,

          799.97 g (16 mol) of O₂ produced  =  704.152 g (16 mol) of CO₂

So,

   3.26 g (0.204 mol) of O₂ will produce  =  X g of CO₂

Solving for X,

                 X =  3.26 g × 704.152 g ÷ 799.97 g

                  X =  2.873 g of CO₂

6 0
3 years ago
Consider the reaction C2H4(g) + H2O(g) --> CH3CH2OH(g)
arsen [322]

Answer:

K = 361.369

Explanation:

C2H4(g) + H2O(g) → CH3CH2OH(g)

∴ ΔG°f(298.15K) CH3CH2OH(g) = - 174.8 KJ/mol

∴ ΔG°f(298.15) C2H4(g) =  68.4 KJ/mol

∴ ΔG°f(298.15) H2O(g) = - 228.6 KJ/mol

⇒ ΔG°f(298.15) = - 174.8 - ( - 228.6 + 68.4 ) = - 14.6 KJ/mol

  • K = e∧(-ΔG°f / RT)

∴ R = 8.314 E-3 KJ/mol.K

∴ T = 298.15 K

⇒ K = e∧(-(-14.6)/((8.314 E-3)(298.15)))

⇒ K = e∧(5.889)

⇒ K = 361.369

6 0
3 years ago
I kinda need this question answered fast please and thank you :)
Aloiza [94]
D. A chemical bond

A mutual attraction between the nuclei and electrons in two different atoms is called a chemical bond, therefore the answer is D
6 0
3 years ago
Reaction of tert−butyl pentyl ether [CH3CH2CH2CH2CH2OC(CH3)3] with HBr forms 1−bromopentane (CH3CH2CH2CH2CH2Br) and compound H.
EleoNora [17]

Answer:The compound H is is 2-Methyl prop-1-ene and its structure can be found in attachment. The m/z value of 2-Methyl prop-1-ene is 56 which clearly matches with the mas spectrum data. The structure can also be ascertained using the provided IR data. The IR data has absorption stretching frequency in the region of 1650cm⁻¹ which is due to the C=C double bond. The stretching frequency at 3150-3000cm⁻¹ is due to the unsaturated C-H bond. The stretching frequency at 3000-2850cm⁻¹ is due to the saturated C-H bonds. Kindly refer attachment for the mechanism.

Explanation:

The reaction of tert-butyl ether with HBr leads to the formation of 1-bromopentane and tertbutyl alcohol.

The tert butyl alcohol formed undergoes E1 elimnation reaction to give 2-Methyl prop-1-ene.

The mass spectra and IR data available for the compound H completely matches with that of 2-Methyl prop-1-ene hence we can ascertain that the compound H is 2-Methyl prop-1-ene.

The m/Z value of 2-Methyl prop-1-ene  is 56 which is in compete accordance with the provided data for compound H .

The IR data also completely matches with the structure of 2-Methyl prop-1-ene as the following Infrared absorption peaks are provided which matches with that of 2-Methyl prop-1-ene :

The absorption stretching frequency in the region of 1650cm⁻¹ corresponds to the  C=C double bond which is clearly evident in 2-Methyl prop-1-ene.

The stretching frequency at 3150-3000cm⁻¹ corresponds to  unsaturated C-H bond.

The stretching frequency at 3000-2850cm⁻¹ is due to the saturated C-H bonds.

The mechanism of the reaction involves the following steps:

1. The oxygen atom in tert-butyl pentyl ether is protonated by treating it with Hydrogen bromide and Br⁻ is lost from hydrogen bromide.

2. Now since the oxygen atom is protonated it turns into a good leaving group and can leave as tertiary butyl alcohol. The eliminated Br⁻ now  attacks in a SN2 manner from the back side at the primary carbon center which leads to the formation of 1-Bromopentane and tertiary-butyl alcohol

3.The tert-butyl alcohol formed further reacts with HBr present to give elimiantion product 2-Methyl prop-1-ene  through E1 elimination mechanism. The OH is protonated  and further it gets eliminated  as H₂O leading to formation of  a tertiary carbocation. The tertiary carbocation formed gives an elimination product of 2-Methyl prop-1-ene .

Kindly refer the attachment for complete reaction mechanism.

8 0
3 years ago
Copper sulfate, when it is dissolved in water, has a blue color. When steel wool is mixed with a copper sulfate solution, the st
jenyasd209 [6]

Answer:

A. The color change from blue to green happens in nature.

Explanation:

The color change is an indicator of a chemical reaction that has occurred. Although color changes are not necessarily good diagnostic tool to measure if a chemical reaction has occurred or not.

  • In this reaction, color changes is quite an effective tool
  • Chemical changes usually involves the formation of a new product from the chemical reaction.
  • Also, the steps are not easily reversible.
  • For this reaction, color change is the most appropriate signal for a chemical change.
4 0
3 years ago
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