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2 years ago

The measurable properties of a substance, such as vapor pressure and surface tension, occur due to the strength of

2 answers:

8 0

Properties of a substance such as vapor pressure and surface tension depend on electrical forces between particles, as given by Coulomb's law.

The vapor pressure refers to how easily a liquid converts to gas while surface tension is the force that makes a liquid surface act as a stretched elastic skin.

Both vapor pressure and surface tension has a lot to do with the degree of polarity in a molecule. Usually, polar molecules have a low vapor pressure and high surface tension due to a high electrical forces between particles, as given by Coulomb's law.

Learn more: brainly.com/question/13440572

Anarel [89]2 years ago

4 0

Answer:

electrical forces between particles, as given by coulombs law.

Explanation:

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For the following reaction, 5.04 grams of nitrogen gas are allowed to react with 8.98 grams of oxygen gas: nitrogen(g) + oxygen(

OLga [1]

Answer:

1. 10.8 g of NO

2. N₂ is the limting reagent

3. 3.2 g of O₂ does not react

Explanation:

We determine the reaction: N₂(g) + O₂(g) → 2NO(g)

We need to determine the limiting reactant, but first we need the moles of each:

5.04 g / 29 g/mol = 0.180 moles N₂

8.98 g / 32 g/mol = 0.280 moles O₂

Ratio is 1:1, so the limiting reactant is the N₂. For 0.280 moles of O₂ I need the same amount, but I only have 0.180 moles of N₂

Ratio is 1:2. 1 mol of N₂ can produce 2 moles of NO

Then, 0.180 moles of N₂ may produce (0.180 .2) / 1 = 0.360 moles NO

If we convert them to mass → 0.360 mol . 30 g/1 mol = 10.8 g

As ratio is 1:1, for 0.180 moles of N₂, I need 0.180 moles of O₂.

As I have 0.280 moles of O₂, (0.280 - 0.180 ) = 0.100 moles does not react.

0.1 moles . 32 g/mol = 3.2 g of O₂ remains after the reaction is complete.

8 0

3 years ago

Read 2 more answers

A gamma ray photon has an energy of 4.75 x 10-14 joules. What is the frequency of this radiation?

Rama09 [41]

The frequency of the radiation is equal to $7.17 \times 10^{19}$ Hertz.

<u>Given the following data:</u>

Photon energy = $4.75 \times 10^{-14}$ Joules

To find the frequency of this radiation, we would use the Planck-Einstein equation.

Mathematically, the Planck-Einstein relation is given by the formula:

$E = hf$

<u>Where:</u>

h is Planck constant.

f is photon frequency.

Substituting the given parameters into the formula, we have;

$4.75 \times 10^{-14} = 6.626 \times 10^{-34} \times F\\\\F = \frac{4.75 \times 10^{-14}}{6.626 \times 10^{-34}}$

Frequency, F = $7.17 \times 10^{19}$ Hertz

4 0

2 years ago

What is the percent composition of carbon in heptane c7h16

Gnom [1K]

Answer: the percent composition of carbon in heptane is 83.9%

Explanation:

<u>1) Atomic masses of the atoms:</u>

C: 12.01 g/mol

H: 1.008 g/mol

<u>2) Molar mass of heptane:</u>

C₇H₁₆: 7 × 12.01 g/mol + 16×1.008 g/mol = 100.2 g/mol

<u>3) Mass of carbon in one mole of heptane:</u>

C₇: 7 × 12.01 g/mol = 84.07 g/mol

<u>3) Percent composition of carbon:</u>

% = (mass in grams of C) / (mass in grams of C₇H₁₆) × 100 =

= (84.07 g/ 100.2 g) × 100 = 83.9% ← answer

8 0

3 years ago

Which two changes would increase the gravitational force between two

scoundrel [369]

Answer:

B. Increase the mass of one of the objects.

E. Decrease the distance between the objects.

Explanation:

To effect an increase in the gravitational force between two objects, the mass of both objects should be increased and the distance between them reduced.

This is derived from the Newton's law of universal gravitation:

It states that "the force of gravity between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance between them".

Therefore, if the mass of the two bodies are increased and the distance between them reduced, the gravitational force of attraction will increase.

4 0

3 years ago

What would be the atomic mass of Nitrogen-14

Maurinko [17]

Answer:

The atomic mass of nitrogen is

<h2><em>You learn more from failure than from success</em></h2>

7 0

2 years ago

Read 2 more answers