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Ber [7]
3 years ago
9

Justin B. Believes that the temperature lowering during the fall months is what causes the color of the leaves to change. He set

up an experiment wherein he placed some plants in 80 degrees rooms and some in 60 degree rooms. He observed the color of the leaves for a total of 1 month. At the end of the month Justin observed that 3/4 of the plants in the 60 degree temperature had begun to change colors and only 1/4 of the plants in the 80 degree temperature began to change colors.
Chemistry
1 answer:
Taya2010 [7]3 years ago
5 0

Answer:

This question is incomplete, the remaining part of the question is:

What is the control group, independent variable and dependent variable?

Control group: Plants placed in 80 degree rooms

Independent variable: Change in temperature

Dependent variable: Change in color of leaves

Explanation:

The independent variable in a scientific experiment is the variable that the experimenter controls or manipulates in order to bring about a change in the dependent variable. In this experiment, the variable manipulated by Justin B is the TEMPERATURE CHANGE.

On the other hand, a variable is said to be dependent if it is the variable that responds to a change made to the independent variable or rather it is the outcome. In this experiment, Justin B is trying to see the outcome on the color change in leaves when exposed to a low temperature, hence, COLOR CHANGE IN LEAVES is the dependent variable.

Control group of an experiment is the group that receives no experimental treatment. It is the group the experimenter considers normal and hence is comparing with his experimental group. In this experiment, Justin B believes the leaves change color in a low temperature, hence, he placed some plants in a lower temperature (60 degree) in order to compare them with when the plants are placed in a higher temperature (80 degree). As far as this experiment is concerned, the plants placed in 80 degrees temperature are believed by Justin B not to undergo color change, hence, they are the CONTROL GROUP while the group he placed in 60 degrees temperature are what he is interested in, making them the EXPERIMENTAL GROUP

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Calculate the mole fraction of the total ions in an aqueous solution prepared by dissolving 0.400 moles of CaI2 in 850.0 g of wa
Evgesh-ka [11]

Answer:

0.00840

Explanation:

The computation of the mole fraction is as follow:

As we know that

Molar mass = Number of grams ÷ number of moles

Or

number of moles = Number of grams ÷ molar mass

Given that

Number of moles of CaI2 = 0.400

And, Molar mass of water = 18.0 g/mol

Now  Number of moles of water is

= 850.0 g ÷ 18.0 g/mol

= 47.22 mol

And, Total number of moles is

= 0.400 + 47.22

= 47.62

So, Molar fraction of CaI2 is

= 0.400 ÷ 47.62

= 0.00840

4 0
3 years ago
When water reaches its boiling point and turns into water vapor what happens to its molecular structure
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When water reaches its boiling point and turns into water vapor, the molecular structure of water remains the same. It is only the state of the substance that is changed in this process. I hope this helps you 
8 0
4 years ago
A compound is formed when 9.03 g
NikAS [45]

The percent composition  of this compound :

Mg = 72.182%

N = 27.818%

<h3>Further explanation</h3>

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9.03 g  Mg

3.48 g  N

Required

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Solution

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3 years ago
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6 0
3 years ago
A solution of CaCl 2 in water forms a mixture that is 42.0 % calcium chloride by mass. If the total mass of the mixture is 839.6
Lerok [7]

Answer : The masses of calcium chloride and water used were, 352.6 g and 487.0 g.

Explanation :

As we are given that 42.0 % calcium chloride by mass that means 42.0 grams of calcium chloride present in 100 grams of solution.

In the solution or mixture, 42.0 % calcium chloride and 58.0 % (100-42.0=58.0) water.

Now we have to determine the mass of calcium chloride for 839.6 grams of solution.

As, 100 grams of solution contains 42.0 grams of calcium chloride

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Thus, the mass of calcium chloride used is, 352.6 grams.

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Mass of water = 839.6 g - 352.6 g

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Thus, the mass of water used is, 487.0 grams.

6 0
3 years ago
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