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max2010maxim [7]
3 years ago
5

What is the velocity (m/s) after 5 seconds of fall

Physics
1 answer:
gregori [183]3 years ago
3 0
5 second fall starting at 0 m/s
ball strikes ground at a speed = 49 meters per second.
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A charged paint is spread in a very thin uniform layer over the surface of a plastic sphere of diameter 10.5 cm, giving it a cha
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The formula that will be used in this problem is E = q/ 4pi*r^2 z where z is the elctric charge constant equal to 8.854  *10 ^-12. The magnitude using r equal to 0.0525 m and q equal to -22.3 *10^-6 C is equal to -22.3 *10^-6/ 4pi*(0.0525)^2 *8.854  *10 ^-12 or equal to -7.272 *10 ^7. The magnitude 5 cm outside the surface is -22.3 *10^-6<span>/ 4pi*(0.0525+0.05)^2 *8.854  *10 ^-12 equal to -1.908 *10^7. 

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8 0
3 years ago
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A 15 N force and a 45 N force act on in object in opposite directions. What is the net force on the object?
vovikov84 [41]

Answer:

30N in the direction the 45N acts.

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Fnet = F1 + F2 (the vector sum of the forces)

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7 0
3 years ago
What is phyical quantity​
puteri [66]

Answer:

physical quantity

Explanation:

All quantity in term of which laws of physics are described and can be measured is called physical quantity

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The ultimate source of energy that powers the sun is
Daniel [21]

The ultimate source of energy that powers the sun is the Mass energy of hydrogen fusing into helium, there is no other process than the annihilation of mass to give energy that has been advocated by Albert Einstein and it is capable of keeping the sun alive.

6 0
3 years ago
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A capacitor with air between its plates ischarged to 60 V and then disconnected fromthe battery. When a piece of glass is placed
-BARSIC- [3]

Answer:

       k = 1.30

Explanation:

For this exercise let's write the capacitance in air and with dielectric

air             C₀ = Q / DV

dielectric  C = k Q / DV

They tell us that the capacitor is charged and then the battery is disconnected, therefore the charge stored on the plate remains constant.

                         

therefore the capacitance a changes to the value

           C = k C₀

The voltage in the presence of dielectric must meet the relationship

           ΔV = ΔV₀ / k

           k = ΔV₀ /ΔV

let's calculate

           k = 60/46

           k = 1.30

5 0
3 years ago
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