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max2010maxim [7]
3 years ago
5

What is the velocity (m/s) after 5 seconds of fall

Physics
1 answer:
gregori [183]3 years ago
3 0
5 second fall starting at 0 m/s
ball strikes ground at a speed = 49 meters per second.
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A transformer has a primary voltage of 115 V and a secondary voltage of 24 V. If the number of turns in the primary is 345, how
Nata [24]

Answer:

C. 72

Explanation:

Transformer: A transformer is an electromagnetic device that uses the property of mutual inductance to change the voltage of alternating supply.

In a ideal transformer,

Vs/Vp = Ns/Np ............................................. Equation 1

Where Vp = primary voltage, Vs = secondary voltage, Ns = Secondary turn, Np = primary turn.

Making Ns the subject of the equation,

Ns =(Vs/Vp)Np .......................................... Equation 2

Given: Vs = 24 V, Vp = 115 V, Np = 345.

Substitute into equation 2

Ns = (24/115)345

Ns = 72 turns.

Thus the number of turns in the secondary = 72 turns.

The right option is C. 72

4 0
3 years ago
The object distance for a concave lens is 8.0 cm, and the image distance is 12.0 cm. The height of the object is 4.0 cm. What is
swat32
The answer for this question, If I am correct, should be answer "D".
3 0
3 years ago
Read 2 more answers
Identify where the sun's rays strike earth most directly and least directly
beks73 [17]
-- Depending on the time of the year, the sun's rays strike Earth
most directly somewhere between the Tropic of Cancer and the
Tropic of Capricorn. 

That's a belt around the Earth's "middle" called the "Tropic Zone". 
The equator is in the middle of it, the Tropic of Cancer is 23.5° North
of the equator, and the Tropic of Capricorn is 23.5° degrees South of it. 

The sun's rays can never be totally direct, straight down onto the Earth's
surface, anywhere outside this belt.


-- The sun's rays strike Earth least directly wherever, and whenever,
the sun is setting.
6 0
3 years ago
Help, I’m stuck. Will give Brainly + 22 pts up for grabs !
Nana76 [90]

Answer:

let the speed of Allegra be x mph, then speed of Elliana is x+4 mph,

time to cover distance for Eliana is 2 hours, time to cover distance for Allegrais 2.5 hours,

since they both cover the same distance you have this,

distance (of Eliana) = distance (of Allegrais ),

distance=speed x time, so we have

speed (of Eliana) x time (of Eliana) = speed (of Allegra) x time (of Allegra),

2(x+4)=2.5x,

solve for x, then substitute back for speeds for Eliana and Allegra,

Eliana's speed = 16 + 4 = 20.

Allegra's speed = 16

6 0
3 years ago
A small space probe of mass 170 kg is launched from a spacecraft near Mars. It travels toward the surface of Mars, where it will
alukav5142 [94]

Answer:

The change  in momentum is  \Delta p =   kg \cdot m/s      

Explanation:

From the question we are told that  

       The mass of the probe is  m = 170 kg

       The location of the prob at time t = 22.9 s is  A  =

       The  momentum at time  t = 22.9 s is  p = < 51000, -7000, 0> kg m/s

        The net force on the probe is  F =  N

Generally the change in momentum is mathematically represented as

              \Delta p = F * \Delta t

The initial time is   22.6 s

 The final time  is  22.9 s

             Substituting values  

           \Delta p =  * (22.9 - 22.6)

            \Delta p =  * (0.3)  

              \Delta p =   kg \cdot m/s        

 

6 0
3 years ago
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