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Ksenya-84 [330]
3 years ago
8

5. Identify the oxidation state of Ca in CaF2(aq). Ca(s) + 2 HF(aq) → CaF2(aq) + H2(g)

Chemistry
1 answer:
NikAS [45]3 years ago
8 0

Answer:

+2

Explanation:

Chemical equation:

Ca + 2HF  →   CaF₂ + H₂

The oxidation state of Ca on left  hand side is 0 while on the right hand side when it form CaF₂ its oxidation state becomes +2 because it loses two. These two electrons are accepted by fluorine and complete its octet while Ca loses its two out most electron to complete the octet.

In this reaction oxidation of calcium takes place and calcium itself is reducing agent.

Reducing agents:

Reducing agents reduced the other element are it self gets oxidized.

Oxidizing agents:

Oxidizing agents oxidize the other elements and itself gets reduced.

Consider another examples.

4KI + 2CuCl₂  →   2CuI  + I₂  + 4KCl

the oxidation state of copper is changed from +2 to +1 so copper get reduced.

CO + H₂O   →  CO₂ + H₂

the oxidation state of carbon is +2 on reactant  side and on product side it becomes  +4 so carbon get oxidized.

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den301095 [7]

Answer:

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6 0
3 years ago
Pre-lab questions 1. a concentration gradient affects the direction that solutes diffuse. describe how molecules move with respe
VLD [36.1K]

Just like how heat moves from a region of higher temperature to a region of lower temperature, molecules also tend to move from a region of higher concentration to a region of lower concentration. This is called natural diffusion and is naturally happening to reach stability.

7 0
3 years ago
For each value of the principal quantum number n, what are the possible values of the electron spin quantum number?
Ede4ka [16]

Answer:

The values for spin quantum number +1/2 and - 1/2

Explanation:

Principal quantum number denoted by (n) is used to describe the shell or orbits that electrons are found. Principal quantum number can assume a value of n= 1,2, 3, 4,5............ which indicates K, L, M, N, O shell respectively.

To know the maximum number of electrons in each shell, the formula (2n²) can be used. The letter 'n' denotes the values of principal quantum number 1,2,3,4

For example

  • n=1 (K shell) has maximum number of 2 electrons
  • n=2 (L shell) has the maximum number of 8 electrons
  • n=3 (M shell) has the maximum number of 18 electrons
  • n=4 (N shell) has the maximum number of 32 electrons

All the electron in each shell will have a spin quantum number of +1/2 and - 1/2. One electron in each degenerate orbital will spin up (+1/2) while the other electron will spin down (-1/2).

7 0
3 years ago
A volume of 125 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. If
VMariaS [17]

Answer:

41.9 g

Explanation:

We can calculate the heat released by the water and the heat absorbed by the steel rod using the following expression.

Q = c × m × ΔT

where,

c: specific heat capacity

m: mass

ΔT: change in temperature

If we consider the density of water is 1.00 g/mol, the mass of water is 125 g.

According to the law of conservation of energy, the sum of the heat released by the water (Qw) and the heat absorbed by the steel (Qs) is zero.

Qw + Qs = 0

Qw = -Qs

cw × mw × ΔTw = -cs × ms × ΔTs

(4.18 J/g.°C) × 125 g × (21.30°C-22.00°C) = -(0.452J/g.°C) × ms × (21.30°C-2.00°C)

ms = 41.9 g

3 0
3 years ago
A copper coin with a mass of 6.30 grams changes temperature in the sunshine from 20.0°C to 32.0°C. How much energy is transferre
mote1985 [20]

Answer:

The energy transferred is  28.5  j

calculation

energy is calculate  MCΔT  formula  where,

M(mass)= 6.30  grams

C(specific heat capacity)= 0.377 j/g

ΔT(change in temperature)= 32.0c- 20 c= 12 c

Energy is therefore= 6.30 g   x 0.377  j/g /c x   12 c =28.5 j

4 0
3 years ago
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