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Nikolay [14]
4 years ago
7

Which solid figures are best for construction? Explain why

Mathematics
2 answers:
Lesechka [4]4 years ago
8 0
A square because you can use to measure in any way you want
Sphinxa [80]4 years ago
4 0
A triangle is the best because it is sturdy. There is no "wiggle room" for the triangle to transform into another shape.
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Factor (4x^3 - 20x^2) -(9x + 45)
stellarik [79]

Answer:

u cannot factor it not possible

Step-by-step explanation:

8 0
4 years ago
1,225 rides was the total number of rides that 35 friends took on a Ferris wheel.
Jet001 [13]
Each friend would have taken a total of 35 rides each. 

This can be verified by multiplying 35 by 35 to get 1225.
8 0
3 years ago
Simplify (4x+5y)(2x-3y) +3xy please
Anettt [7]
8x^2+xy-15y^2

If you need to show work I can put it in the comments :)
5 0
3 years ago
Prove that:
Likurg_2 [28]

Step-by-step explanation:

16⁴ - 2¹³ - 4⁵

= 2¹⁶ - 2¹³ - 2¹⁰

= 2¹⁰(2⁶ - 2³ - 1)

= 2¹⁰(64 - 8 - 1)

= 2¹⁰ * 55

= 2¹⁰ * 5 * 11.

Since it contains 11 in its prime factorization, it is divisible by 11. (Proven)

3 0
3 years ago
If you draw four cards at random from a standard deck of 52 cards, what is the probability that all 4 cards have distinct charac
mezya [45]

There are \binom{52}4 ways of drawing a 4-card hand, where

\dbinom nk = \dfrac{n!}{k!(n-k)!}

is the so-called binomial coefficient.

There are 13 different card values, of which we want the hand to represent 4 values, so there are \binom{13}4 ways of meeting this requirement.

For each card value, there are 4 choices of suit, of which we only pick 1, so there are \binom41 ways of picking a card of any given value. We draw 4 cards from the deck, so there are \binom41^4 possible hands in which each card has a different value.

Then there are \binom{13}4 \binom41^4 total hands in which all 4 cards have distinct values, and the probability of drawing such a hand is

\dfrac{\dbinom{13}4 \dbinom41^4}{\dbinom{52}4} = \boxed{\dfrac{2816}{4165}} \approx 0.6761

4 0
2 years ago
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