Answer: 1/12
1/4 divided by 3/1
KCF:Keep the first fraction, Change the sign to muplication, Flip the second fraction.
1/4* 31
1*1=1
4*3=12
1/12
Answer:
Option (A)
Explanation:
The correlation of rocks is usually defined as a technique that helps in determining the age of the rocks that are mostly characterized by the presence of similar fossil/fossil assemblages. These fossils that are used are mainly the index fossils that appeared for a short geological time and were very widely distributed on earth's surface. By determining the age of these fossils, the rocks in which these fossils are found were concluded to be formed during the same age.
This method is efficient to use for the geologists where the fossils acts as a tool to determine the age of the rocks. For the correlation of rocks, scientists look for a similar type of fossils that are found in different places.
Thus, the correct answer is option (A).
Answer:
Blue and Green marbles
Explanation:
We have been given that:
Number of Marbles:
Blue(Protons) = 3
Green(Neutrons) = 4
Red (Electrons) = 3
The marble that should be placed in the nucleus of a lithium atom = ?
Solution:
The nucleus of an atom is made up of protons and neutrons.
Protons are the positively charged particles in an atom.
Neutrons do not carry any charges.
So;
The marble in the nucleus are the Blue and Green marbles.
Answer:
The concentration after 115 seconds is 0.0496 M
Explanation:
Applying integrated rate law for a first-order reaction, we will have;
![[A]_t = [A]_0e^{-kt}](https://tex.z-dn.net/?f=%5BA%5D_t%20%3D%20%5BA%5D_0e%5E%7B-kt%7D)
where;
is the concentration at a time t
is the initial concentration
k is the rate constant for the reaction
t is the given time
Given;
= 0.05 M
k = 6.2 x 10⁻⁵ mol L⁻¹s⁻¹
t = 115 seconds
Substitute these values and solve for
![[A]_t = [A]_0e^{-kt} = (0.05)*e^{-(6.2X10^{-5}*115)}\\\\](https://tex.z-dn.net/?f=%5BA%5D_t%20%3D%20%5BA%5D_0e%5E%7B-kt%7D%20%3D%20%280.05%29%2Ae%5E%7B-%286.2X10%5E%7B-5%7D%2A115%29%7D%5C%5C%5C%5C)
![[A]_t = (0.05)(0.9929) =0.0496 M](https://tex.z-dn.net/?f=%5BA%5D_t%20%3D%20%280.05%29%280.9929%29%20%3D0.0496%20M)
Therefore, the concentration after 115 seconds is 0.0496 M
Answer:
Look at the pictures. On the 1 are compounds A and B. Compound c from b is on the 2nd image. Compound D is on 3rd image. Compound E is the same for compound C.
Explanation:
So for compound A sodium acetylide substitutes nucleophilicaly one Br on 1,12-dibromododecane. Then to obtain compound B sodium amide eliminates another Br. So for acetylene and alkene groups ozonolysis works the same way and we obtain diacid. Lyndlar catalyst works only on alkynes and make cis-alkenes from them. but we have a terminal alkyne for wich no isomers may occur. Pt reduction provides alkanes from both alenes and akynes. And sodium ammonia reduction works only on alkynes to provide trans-alkenes but, as I've said, isomers are not our case. So compounds E and C are the same and undergo same reaction with ozone.