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never [62]
3 years ago
11

Which of these is an oxidation half-reaction?

Chemistry
1 answer:
Zepler [3.9K]3 years ago
6 0

Answer:

E= mc sqared

Explanation:

;) lol

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Please help on my test
Alisiya [41]

Answer:

C

Explanation:

5 0
3 years ago
How many molecules are in 3.8 grams of c6h6
kogti [31]

Answer:

i dont really know how to explain but its the math

Explanation:

296.8249919999934

7 0
3 years ago
Read 2 more answers
Calculate the mass in grams, in 2.28 mol of SO3 .
Ulleksa [173]

The mass of 2.28 mol of SO₃ is 182.4 g.

<h3>What is mass?</h3>

Mass can be defined as the quantity of matter a body contains.

The S.I unit of mass is kilogram (kg). other units of mass include grams (g), milligram (mg), microgram (μg) etc.

<h3>What is a matter?</h3>

A matter is anything that has mass and occupies space. Matter exist in three states.

  • Solid state
  • Liquid state
  • Gaseous state

To calculate the mass of 2.28 mol of SO₃, we use the formula below.

Formula:

  • m = nM............. Equation 1

⇒ Where:

  • m = mass of SO₃
  • n = number of mole of SO₃
  • M = molar mass of SO₃

From the question,

Given:

  • n = 2.28 mol
  • M = 80 g/mol

Substitute these values into equation 1

  • m = 2.28×80
  • m = 182.4 g

Hence, the mass of 2.28 mol of SO₃ is 182.4 g.

Learn more about mass here: brainly.com/question/19385703

#SPJ1

7 0
2 years ago
The mass of an object is described in ________. a.meters b.cubic meters c.liters d.grams
Viefleur [7K]
The mass of an object is describes in D. Grams.
3 0
3 years ago
What is the energy of a photon of yellow light with a frequency of 5.2 x 10¹⁴ Hz?<br><br>​
3241004551 [841]

Answer:

3.4x10⁻¹⁹J is the energy of the photon

Explanation:

To find the energy of a photon from its frequency we must use the equation:

E = hf

<em>Where E is the energy of the photon in J, our incognite</em>

<em>h is Planck's constant = 6.6262x10⁻³⁴Js</em>

<em>And f is the frequency = 5.2x10¹⁴Hz = 5.2x10¹⁴s⁻¹</em>

<em />

Replacing:

E = 6.6262x10⁻³⁴Js*5.2x10¹⁴s⁻¹

E = 3.4x10⁻¹⁹J is the energy of the photon

<em />

4 0
2 years ago
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