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Irina18 [472]
3 years ago
9

How many grams of ammonium sulfide are in 2.35 mile of ammonium sulfide

Chemistry
1 answer:
Afina-wow [57]3 years ago
8 0

Answer:

160.18 grams

Explanation:

You find the molar mass which is 68.16 g/mol and multiply that by the number of moles present.

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What is the molarity of a solution made by dissolving 14.8 g of ammonium hydroxide NH4OH, in enough water to make 250.0 mL of so
kicyunya [14]

Answer:

Molarity= 1.69M

Explanation:

m= 14.8, Mm= 35, V= 0.25dm3, C= ?

Moles = m/M= C×V

Substitute and Simplify

m/M= C×V

14.8/35= C×0.25

C= 1.69M

6 0
3 years ago
Which chemical reaction needs more energy to break bonds in the reactants
MA_775_DIABLO [31]

Answer:An endothermic reaction

Explanation: In an endothermic reaction, it takes more energy to break the bonds of the reactants than is released when the bonds in the products are formed. In an endothermic reaction, the temperature goes down.

6 0
3 years ago
Read 2 more answers
Select the correct answer.
GREYUIT [131]

Answer:HNO3 + NaOH → H2O + NaNO3

Explanation:

8 0
3 years ago
How many moles of HNO3 are present if 4.90×10−2 mol of Ba(OH)2 was needed to neutralize the acid solution?
Amiraneli [1.4K]

Answer:

0.098 moles

Explanation:

Let y represent the number of moles present

1 mole of Ba(OH)₂ contains 2 moles of OH- ions.

Hence, 0.049 moles of Ba(OH)2 contains y moles of OH- ions.

To get the y moles, we then do cross multiplication

1 mole *  y mole = 2 moles * 0.049 mole

y mole = 2 * 0.049 / 1

y mole =  0.098 moles of OH- ions.

1 mole of OH- can neutralize 1 mole of H+

Therefore, 0.098 moles of HNO₃ are present.

3 0
3 years ago
Given a 1.50 Liters of solution that contains 62.5 grams of magnesium oxide. What is the Molarity of that solution? Please show
zhenek [66]
Given:
1.50 L
62.5 grams
and the MM of MgO: 40.31 g/mol

Molarity: mol/L

First, find mol.

62.5 g x 1mole ÷ 40.31 g = 1.55 mol

then divide mol and the given liters

1.55mol ÷ 1.50 L= 1.03 M
3 0
3 years ago
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