The correct awnser is true i belive
TRUE
Answer:
Not sure which statements were give to you for this question, but the vehicle's acceleration from noon to 2:00 PM was <em>zero</em>, the vehicle had a <em>positive</em> acceleration between 2:00 pm and 3:00 pm, and the vehicle had a <em>negative</em> acceleration at 4:30 PM.
Explanation:
From 12:00 PM to 2:00 PM, the vehicle traveled at a constant velocity of 70 MPH, meaning there wasn't any change to the speed. The velocity <em>remained the same</em>. An hour later, the velocity of the vehicle <em>increased</em> to 80 MPH, and finally at 4:30 PM, the velocity of the car <em>decreased </em>and was at 40 MPH.
Answer:
Velocity
Explanation:
the speed of something in a given direction
Answer:
<h2>
The force is </h2>
Explanation:
According to newtons law on gravitation formula, which we are going to apply,
Where G represents universal gravitation constant,
Given data
m1= 90 kg
m2= 60 kg
d= 1 m
Substituting our given data into the formula we have
Answer:
The shortest distance in which you can stop the automobile by locking the brakes is 53.64 m
Explanation:
Given;
coefficient of kinetic friction, μ = 0.84
speed of the automobile, u = 29.0 m/s
To determine the the shortest distance in which you can stop an automobile by locking the brakes, we apply the following equation;
v² = u² + 2ax
where;
v is the final velocity
u is the initial velocity
a is the acceleration
x is the shortest distance
First we determine a;
From Newton's second law of motion
∑F = ma
F is the kinetic friction that opposes the motion of the car
-Fk = ma
but, -Fk = -μN
-μN = ma
-μmg = ma
-μg = a
- 0.8 x 9.8 = a
-7.84 m/s² = a
Now, substitute in the value of a in the equation above
v² = u² + 2ax
when the automobile stops, the final velocity, v = 0
0 = 29² + 2(-7.84)x
0 = 841 - 15.68x
15.68x = 841
x = 841 / 15.68
x = 53.64 m
Thus, the shortest distance in which you can stop the automobile by locking the brakes is 53.64 m